用verilog代码设计并实现一个FSM。该FSM的功能:输入一个8位值,然后判断输入值是否有相等的0位和1位。如果输入值具有相同数量的0和1,则微处理器输出一个1;否则,则输出0。下面给出算法:Count = 0; INPUT N; WHILE (N≠0){ IF (N(0) = 1) THEN Count = Count + 1 ;END IF N = N >> 1 } OUTPUT (Count = 4)
时间: 2024-01-24 21:17:25 浏览: 26
以下是使用Verilog语言实现该功能的FSM代码:
```verilog
module EqualZerosOnes(
input clk,
input rst,
input [7:0] data_in,
output reg out
);
// 定义状态枚举类型
typedef enum logic [2:0] {
IDLE,
COUNT_ZEROS,
COUNT_ONES,
OUTPUT_RESULT
} state_t;
// 定义状态和计数器寄存器
reg [2:0] state_reg;
reg [3:0] counter_reg;
// 定义状态转移条件
wire condition1 = (state_reg == IDLE) && (data_in != 8'h00);
wire condition2 = (state_reg == COUNT_ZEROS) && (data_in != 8'h00);
wire condition3 = (state_reg == COUNT_ONES) && (data_in != 8'h00);
wire condition4 = (state_reg == OUTPUT_RESULT);
// 定义状态转移表
// 当前状态 输入 下一状态 输出操作
// --------------------------------------
// IDLE !=0 COUNT_ZEROS -
// COUNT_ZEROS 1 COUNT_ONES -
// COUNT_ZEROS 0 COUNT_ZEROS -
// COUNT_ONES 0 COUNT_ONES -
// COUNT_ONES 1 OUTPUT_RESULT -
// OUTPUT_RESULT - IDLE out<=1 if count_reg==4 else out<=0
always @ (posedge clk, posedge rst) begin
if (rst) begin
state_reg <= IDLE;
counter_reg <= 4'd0;
out <= 1'b0;
end else begin
case(state_reg)
IDLE: begin
if (condition1) begin
state_reg <= COUNT_ZEROS;
end
end
COUNT_ZEROS: begin
if (condition2) begin
if (data_in[0] == 1'b0) begin
counter_reg <= counter_reg + 1;
end
state_reg <= COUNT_ONES;
end else if (~condition2) begin
state_reg <= COUNT_ZEROS;
end
end
COUNT_ONES: begin
if (condition3) begin
if (data_in[0] == 1'b1) begin
counter_reg <= counter_reg + 1;
end
state_reg <= COUNT_ZEROS;
end else if (~condition3) begin
state_reg <= COUNT_ONES;
end
end
OUTPUT_RESULT: begin
state_reg <= IDLE;
if (counter_reg == 4'd4) begin
out <= 1'b1;
end else begin
out <= 1'b0;
end
counter_reg <= 4'd0;
end
endcase
end
end
endmodule
```
该FSM共包含4个状态:IDLE、COUNT_ZEROS、COUNT_ONES和OUTPUT_RESULT。初始状态为IDLE,输入不为0时进入COUNT_ZEROS状态,遍历输入值的所有位,并在COUNT_ZEROS和COUNT_ONES状态之间进行转移,计算输入值中0和1的数量。当所有位遍历完后,进入OUTPUT_RESULT状态,输出计数器的值是否等于4。最后返回到IDLE状态,准备接收下一个输入值。
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