编写程序,判断列表ls1=["pythonn","pythhon","ppython","pytthon","pythoon"]中哪个元素含有两个字母“t”,输出该元素
时间: 2023-06-04 19:05:23 浏览: 47
程序如下:
```python
ls1=["pythonn","pythhon","ppython","pytthon","pythoon"]
for i in ls1:
if i.count("t") == 2:
print(i)
```
输出结果为:
```
pytthon
```
相关问题
判断列表ls1=["pythonn","pythhon","ppython","pytthon","pythoon"]中哪个元素含有两个字母“t”,输出该元素用python程序
可以使用以下 Python 代码来解决这个问题:
```python
ls1 = ["pythonn", "pythhon", "ppython", "pytthon", "pythoon"]
for s in ls1:
if s.count("t") == 2:
print(s)
```
输出结果为:
```
pytthon
```
这个代码使用了一个 for 循环来遍历列表中的每个元素,然后使用 count() 方法来计算该元素中字母 "t" 的数量。如果数量为 2,就说明该元素符合要求,就输出该元素。
用python判断列表ls1=["pythonn","pythhon","ppython","pytthon","pythoon"]中哪个元素含有两个字母“t”,输出该元素
你可以使用一个循环遍历列表ls1中的每个元素,然后使用count()函数计算"t"出现的次数。如果出现次数为2,则打印该元素。
以下是示例代码:
```python
ls1 = ["pythonn","pythhon","ppython","pytthon","pythoon"]
for element in ls1:
if element.count("t") == 2:
print(element)
```
这将输出:
```
pytthon
```