What is the mnemonic code of the machine code “0x682A4327”
时间: 2024-02-17 19:59:53 浏览: 66
The mnemonic code of the machine code "0x682A4327" depends on the specific architecture and instruction set being used. However, I can provide an example of the mnemonic code for this instruction in ARMv7-A assembly language.
In ARMv7-A assembly language, the machine code "0x682A4327" would be decoded as:
```
LDR r3, [r5, r7, LSL #2]
```
This instruction loads a 32-bit (4-byte) value from the memory address at `r5 + r7 * 4` into register `r3`. The mnemonic code for this instruction would be:
```
LDR r3, [r5, r7, LSL #2]
```
Note that the exact mnemonic code for this instruction may differ depending on the specific architecture and implementation.
相关问题
What is the machine code of the mnemonic code “LDR r3, [r5, #2]”
The machine code of the mnemonic code "LDR r3, [r5, #2]" depends on the specific architecture and instruction set being used. However, I can provide an example of the machine code for this instruction in ARMv8-A assembly language.
In ARMv8-A assembly language, the instruction "LDR r3, [r5, #2]" would be encoded as:
```
LDR X3, [X5, #2]
```
This instruction loads a 64-bit (8-byte) value from the memory address at `X5 + 2` into register `X3`. The machine code for this instruction would be:
```
0xB8 0x21 0x58 0xB8
```
This is represented as four bytes in hexadecimal notation. Note that the exact machine code for this instruction may differ depending on the specific architecture and implementation.
What is the machine code of the mnemonic code “LDR r8, [r7, #4]”
The machine code of the mnemonic code "LDR r8, [r7, #4]" depends on the specific architecture and instruction set being used. However, I can provide an example of the machine code for this instruction in ARMv7-A assembly language.
In ARMv7-A assembly language, the instruction "LDR r8, [r7, #4]" would be encoded as:
```
LDR r8, [r7, #4]
```
This instruction loads a 32-bit (4-byte) value from the memory address at `r7 + 4` into register `r8`. The machine code for this instruction would be:
```
0x68 0x47
```
This is represented as two bytes in hexadecimal notation. Note that the exact machine code for this instruction may differ depending on the specific architecture and implementation.
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