帮我用python新建一个列表,列表中有四个元素,列表中的元素发生变化就打印输出这个列表的程序
时间: 2023-10-30 15:44:36 浏览: 77
以下一个使用Python编写的,新建一个包含四个元素的列表,并在列表元素发生变化时打输出整个列表:
```python
my = [1, 2, 3, 4] # 创建一个包含四个元素的列表
# 定义一个函数,用打印输出列表
def print_list(lst):
print("List updated:", lst)
while True:
# 获取用户输入的索引和新的值
index = int(input("Enter the index to update (0-3) (press -1 to quit): "))
if index == -1:
break # 如果输入为 -1,则退出循环
value = input("Enter the new value: ")
my_list[index] = value # 更新列表中指定索引的元素
print_list(my_list) # 调用函数打印输出列表
```
运行以上程序,你可以通过输入索引和新的值来更新列表中的元素,并在每次更新时打印输出整个列表。当你输入 -1 时,程序会退出循环。
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