代码优化 private int calculateScore() { int singleChoiceScore = 0; int multiChoiceScore = 0; // 计算单选题得分 RadioGroup singleChoiceGroup = findViewById(R.id.rg_1); int selectedSingleChoiceId = singleChoiceGroup.getCheckedRadioButtonId(); if (selectedSingleChoiceId == R.id.rb_1) { singleChoiceScore = 50; } // 计算多选题得分 CheckBox ck1 = findViewById(R.id.ck_1); CheckBox ck2 = findViewById(R.id.ck_2); CheckBox ck3 = findViewById(R.id.ck_3); CheckBox ck4 = findViewById(R.id.ck_4); CheckBox ck5 = findViewById(R.id.ck_5); int checkedCount = 0; // 统计选中的选项数量 if (ck1.isChecked()) { checkedCount++; } if (ck2.isChecked()) { checkedCount++; } if (ck3.isChecked()) { checkedCount++; } if (ck4.isChecked()) { checkedCount++; } if (ck5.isChecked()) { checkedCount++; } if (checkedCount == 0) { multiChoiceScore = 0; } else if (checkedCount == 2) { multiChoiceScore = 20; } else if (checkedCount == 3) { multiChoiceScore = 30; } else if (checkedCount == 4) { multiChoiceScore = 50; } return singleChoiceScore + multiChoiceScore; } private String calculateGrade(int score) { if (score < 60) { return "不及格"; } else if (score < 70) { return "合格"; } else if (score < 90) { return "良好"; } else { return "优秀"; } }

可以对代码进行如下优化：

1. 将计算多选题得分的部分抽取出来，封装成一个方法，提高代码的可复用性和可读性。

2. 通过使用数组和循环来简化计算多选题得分的代码。

3. 将计算成绩等级的代码改为使用 switch/case 语句，提高代码的可读性。

优化后的代码如下：

private int calculateScore() {
    int singleChoiceScore = 0;
    int multiChoiceScore = calculateMultiChoiceScore();

    // 计算单选题得分
    RadioGroup singleChoiceGroup = findViewById(R.id.rg_1);
    int selectedSingleChoiceId = singleChoiceGroup.getCheckedRadioButtonId();
    if (selectedSingleChoiceId == R.id.rb_1) {
        singleChoiceScore = 50;
    }

    return singleChoiceScore + multiChoiceScore;
}

private int calculateMultiChoiceScore() {
    CheckBox[] checkBoxes = new CheckBox[] {
            findViewById(R.id.ck_1),
            findViewById(R.id.ck_2),
            findViewById(R.id.ck_3),
            findViewById(R.id.ck_4),
            findViewById(R.id.ck_5)
    };
    int checkedCount = 0;
    for (int i = 0; i < checkBoxes.length; i++) {
        if (checkBoxes[i].isChecked()) {
            checkedCount++;
        }
    }
    switch (checkedCount) {
        case 0:
            return 0;
        case 2:
            return 20;
        case 3:
            return 30;
        case 4:
            return 50;
        default:
            return 0;
    }
}

private String calculateGrade(int score) {
    switch (score / 10) {
        case 6:
            return "合格";
        case 7:
            return "良好";
        case 8:
        case 9:
        case 10:
            return "优秀";
        default:
            return "不及格";
    }
}