这段代码无法正常运行,请检查
时间: 2023-12-09 08:03:48 浏览: 47
非常抱歉,可能是因为我在转换中不小心出现了错误。以下是正确的代码,再次向您道歉:
```c
#include <stdio.h>
#include <math.h>
int solve(double a, double b, double c);
int main() {
double a, b, c;
printf("Please enter the coefficients a, b, c of the quadratic equation:\n");
scanf("%lf %lf %lf", &a, &b, &c);
int num = solve(a, b, c);
if (num == 0) {
printf("This quadratic equation has no real roots!\n");
} else if (num == 1) {
printf("This quadratic equation has one real root: %.2lf\n", -b / (2 * a));
} else {
double x1 = (-b + sqrt(b * b - 4 * a * c)) / (2 * a);
double x2 = (-b - sqrt(b * b - 4 * a * c)) / (2 * a);
printf("This quadratic equation has two real roots: %.2lf and %.2lf\n", x1, x2);
}
return 0;
}
int solve(double a, double b, double c) {
double delta = b * b - 4 * a * c;
if (delta > 0) {
return 2;
} else if (delta == 0) {
return 1;
} else {
return 0;
}
}
```
请再次检查。如果您还有问题,请告诉我,我会尽力帮助您。
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