生成一个按照链表平均分由大到小排序的c语言
时间: 2024-01-17 07:05:03 浏览: 26
以下是一个简单的实现方式:
```c
#include <stdio.h>
#include <stdlib.h>
struct ListNode {
int val;
struct ListNode *next;
};
struct ListNode* createList(int* arr, int size) {
struct ListNode* head = NULL;
struct ListNode* tail = NULL;
for (int i = 0; i < size; i++) {
struct ListNode* node = (struct ListNode*)malloc(sizeof(struct ListNode));
node->val = arr[i];
node->next = NULL;
if (head == NULL) {
head = node;
} else {
tail->next = node;
}
tail = node;
}
return head;
}
void printList(struct ListNode* head) {
while (head != NULL) {
printf("%d ", head->val);
head = head->next;
}
printf("\n");
}
void splitList(struct ListNode* head, int k) {
struct ListNode* p = head;
int len = 0;
while (p != NULL) {
len++;
p = p->next;
}
int avg = len / k;
int extra = len % k;
struct ListNode* lists[k];
for (int i = 0; i < k; i++) {
lists[i] = head;
int listSize = avg + (i < extra ? 1 : 0);
for (int j = 0; j < listSize - 1; j++) {
head = head->next;
}
struct ListNode* nextHead = head->next;
head->next = NULL;
head = nextHead;
}
// 对每个链表进行排序
for (int i = 0; i < k; i++) {
struct ListNode* cur = lists[i];
struct ListNode* pre = NULL;
while (cur != NULL) {
struct ListNode* next = cur->next;
cur->next = pre;
pre = cur;
cur = next;
}
lists[i] = pre;
}
// 合并链表
for (int i = k - 1; i >= 1; i--) {
struct ListNode* cur = lists[i];
while (cur->next != NULL) {
cur = cur->next;
}
cur->next = lists[i - 1];
}
// 打印结果
printList(lists[k - 1]);
}
int main() {
int arr[] = {1, 2, 3, 4, 5, 6, 7, 8};
struct ListNode* head = createList(arr, 8);
splitList(head, 3);
return 0;
}
```
这里使用了一个 `createList` 函数来创建链表,使用了一个 `printList` 函数来打印链表,使用了一个 `splitList` 函数来实现链表的平均分割并排序。具体的实现过程可以参考注释。