帮我写C语言的银行家算法,并给出代码
时间: 2023-05-16 11:05:59 浏览: 91
好的,银行家算法是一种避免死锁的算法,它可以保证系统资源的安全分配。以下是C语言的银行家算法代码:
#include <stdio.h>
#include <stdbool.h>
#define MAX_PROCESS 10
#define MAX_RESOURCE 10
int available[MAX_RESOURCE];
int max[MAX_PROCESS][MAX_RESOURCE];
int allocation[MAX_PROCESS][MAX_RESOURCE];
int need[MAX_PROCESS][MAX_RESOURCE];
bool finish[MAX_PROCESS];
int n, m;
bool is_safe() {
int work[MAX_RESOURCE];
for (int i = 0; i < m; i++) {
work[i] = available[i];
}
bool finish_all = false;
while (!finish_all) {
finish_all = true;
for (int i = 0; i < n; i++) {
if (!finish[i]) {
bool can_finish = true;
for (int j = 0; j < m; j++) {
if (need[i][j] > work[j]) {
can_finish = false;
break;
}
}
if (can_finish) {
finish[i] = true;
for (int j = 0; j < m; j++) {
work[j] += allocation[i][j];
}
finish_all = false;
}
}
}
}
for (int i = 0; i < n; i++) {
if (!finish[i]) {
return false;
}
}
return true;
}
int main() {
printf("请输入进程数和资源数:\n");
scanf("%d%d", &n, &m);
printf("请输入每个进程需要的资源数:\n");
for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++) {
scanf("%d", &max[i][j]);
}
}
printf("请输入每个进程已经分配的资源数:\n");
for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++) {
scanf("%d", &allocation[i][j]);
need[i][j] = max[i][j] - allocation[i][j];
}
}
printf("请输入每种资源的总数:\n");
for (int i = 0; i < m; i++) {
scanf("%d", &available[i]);
}
if (is_safe()) {
printf("系统是安全的!\n");
} else {
printf("系统是不安全的!\n");
}
return 0;
}
希望这个代码能够帮到你!