用c语言编写一个简单个位数运算器
时间: 2023-05-26 18:01:54 浏览: 39
```
#include <stdio.h>
int main() {
int num1, num2;
char operator;
printf("请输入两个数字和运算符(如1 + 2): ");
scanf("%d %c %d", &num1, &operator, &num2);
int result;
switch (operator) {
case '+':
result = num1 + num2;
break;
case '-':
result = num1 - num2;
break;
case '*':
result = num1 * num2;
break;
case '/':
result = num1 / num2;
break;
default:
printf("输入运算符不正确\n");
return 1;
}
printf("结果为: %d\n", result);
return 0;
}
```
编译运行:
```
$ gcc calculator.c -o calculator
$ ./calculator
请输入两个数字和运算符(如1 + 2): 3 * 4
结果为: 12
```
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