Spring整合Mybatis 使用注册的用户名和密码进行登录，登录成功展示用户名.密码.角色名

首先，您需要配置Spring和Mybatis的整合。这里提供一份示例配置文件：

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:context="http://www.springframework.org/schema/context"
       xmlns:mybatis-spring="http://mybatis.org/schema/mybatis-spring"
       xsi:schemaLocation="
        http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
        http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd
        http://mybatis.org/schema/mybatis-spring http://mybatis.org/schema/mybatis-spring.xsd">

    <!-- 数据源配置 -->
    <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
        <property name="driverClassName" value="com.mysql.jdbc.Driver"/>
        <property name="url" value="jdbc:mysql://localhost:3306/test"/>
        <property name="username" value="root"/>
        <property name="password" value="123456"/>
    </bean>

    <!-- Mybatis配置 -->
    <bean id="sqlSessionFactory" class="org.mybatis.spring.SqlSessionFactoryBean">
        <property name="dataSource" ref="dataSource"/>
        <property name="typeAliasesPackage" value="com.example.entity"/>
        <!-- mybatis配置文件 -->
        <property name="configLocation" value="classpath:mybatis-config.xml"/>
    </bean>

    <!-- Mapper接口扫描 -->
    <mybatis-spring:scan base-package="com.example.mapper"/>

    <!-- 事务管理器配置 -->
    <bean id="transactionManager" class="org.springframework.jdbc.datasource.DataSourceTransactionManager">
        <property name="dataSource" ref="dataSource"/>
    </bean>

    <!-- 开启注解事务 -->
    <tx:annotation-driven transaction-manager="transactionManager"/>

    <!-- 开启Spring注解 -->
    <context:annotation-config/>
    <context:component-scan base-package="com.example"/>

</beans>

接下来，您需要编写登录功能的Service和DAO层代码。这里提供一个简单的示例：

@Service
public class UserService {
    
    @Autowired
    private UserMapper userMapper;
    
    public User login(String username, String password) {
        User user = userMapper.findByUsernameAndPassword(username, password);
        return user;
    }
    
}

@Mapper
public interface UserMapper {
    
    User findByUsernameAndPassword(@Param("username") String username, @Param("password") String password);
    
}

最后，您需要编写Controller层代码来响应用户登录的请求，并返回相应的信息：

@RestController
public class UserController {
    
    @Autowired
    private UserService userService;
    
    @PostMapping("/login")
    public Map<String, Object> login(@RequestParam("username") String username, @RequestParam("password") String password) {
        Map<String, Object> result = new HashMap<>();
        User user = userService.login(username, password);
        if (user != null) {
            result.put("success", true);
            result.put("username", user.getUsername());
            result.put("password", user.getPassword());
            result.put("role", user.getRole());
        } else {
            result.put("success", false);
            result.put("message", "用户名或密码错误");
        }
        return result;
    }
    
}

这样，当用户通过POST请求访问`/login`接口并传递正确的用户名和密码时，您将会得到一个JSON格式的响应，其中包含用户名、密码和角色名。