C语言：创建链表，提交与自己学号相邻的两位同学的学号与一门考试成绩，编程建立由这三组数据结点组成的简单链表。输入形式：三组同学的学号后三位，成绩。输出形式：链表各结点 的数据。样例输入：201，98,202,94,203,89 样例输出 [num=201，score=98] [num=202,score=94]

#include <stdio.h>
#include <stdlib.h>

typedef struct node {
    int num;
    int score;
    struct node *next;
} NODE;

NODE *new_node(int num, int score) {
    NODE *node = (NODE *) malloc(sizeof(NODE));
    node->num = num;
    node->score = score;
    node->next = NULL;
    return node;
}

NODE *add_node(NODE *head, int num, int score) {
    NODE *node = new_node(num, score);
    if (head == NULL) {
        head = node;
    } else {
        NODE *p = head;
        while (p->next != NULL) {
            p = p->next;
        }
        p->next = node;
    }
    return head;
}

void print_list(NODE *head) {
    NODE *p = head;
    while (p != NULL) {
        printf("[num=%d, score=%d] ", p->num, p->score);
        p = p->next;
    }
}

int main() {
    int num1, num2, num3, score1, score2, score3;
    printf("请输入三组同学的学号后三位和成绩：\n");
    scanf("%d%d%d%d%d%d", &num1, &score1, &num2, &score2, &num3, &score3);
    
    NODE *head = NULL;
    head = add_node(head, num1, score1);
    head = add_node(head, num2, score2);
    head = add_node(head, num3, score3);
    
    printf("链表各节点的数据为：");
    print_list(head);
    printf("\n");
    
    return 0;
}