绘制一个派大星，python

好的，让我来为您编写一段Python代码，用于绘制一个派大星：

import turtle

# 创建一个画布
canvas = turtle.Screen()

# 创建一个海绵宝宝对象，并设置颜色和线宽
spongebob = turtle.Turtle()
spongebob.color("yellow")
spongebob.pensize(5)

# 绘制派大星的头部和眼睛
spongebob.begin_fill()
spongebob.circle(100)
spongebob.end_fill()

spongebob.penup()
spongebob.goto(-50, 120)
spongebob.color("white")
spongebob.pendown()
spongebob.begin_fill()
spongebob.circle(20)
spongebob.end_fill()

spongebob.penup()
spongebob.goto(50, 120)
spongebob.pendown()
spongebob.begin_fill()
spongebob.circle(20)
spongebob.end_fill()

# 绘制派大星的鼻子和嘴巴
spongebob.penup()
spongebob.goto(0, 80)
spongebob.pendown()
spongebob.color("brown")
spongebob.begin_fill()
spongebob.circle(30)
spongebob.end_fill()

spongebob.penup()
spongebob.goto(-60, 20)
spongebob.pendown()
spongebob.color("red")
spongebob.begin_fill()
spongebob.circle(20, 180)
spongebob.end_fill()

# 绘制派大星的裤子和鞋子
spongebob.penup()
spongebob.goto(-70, -40)
spongebob.pendown()
spongebob.color("brown")
spongebob.begin_fill()
for i in range(2):
    spongebob.forward(140)
    spongebob.left(90)
    spongebob.forward(60)
    spongebob.left(90)
spongebob.end_fill()

spongebob.penup()
spongebob.goto(-50, -100)
spongebob.pendown()
spongebob.begin_fill()
spongebob.circle(30)
spongebob.end_fill()

spongebob.penup()
spongebob.goto(50, -100)
spongebob.pendown()
spongebob.begin_fill()
spongebob.circle(30)
spongebob.end_fill()

# 隐藏画笔
spongebob.hideturtle()

# 显示画布
canvas.mainloop()

这段代码将使用Python中的turtle库来绘制一个派大星，包括头部、眼睛、鼻子、嘴巴、裤子和鞋子。运行代码，您将在屏幕上看到一个可爱的派大星。