java猜数字游戏复杂版

好的，下面是一个复杂版的Java猜数字游戏：

import java.util.Scanner;

public class GuessNumberGame {

    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);
        int min = 1;
        int max = 100;
        int range = max - min + 1;
        int numToGuess = (int) (Math.random() * range) + min;
        int numGuesses = 0;
        int guess = 0;
        int[] guesses = new int[10];

        System.out.println("I am thinking of a number between " + min + " and " + max + ".");
        System.out.println("You have 10 guesses to find the number.");

        while (numGuesses < 10) {
            System.out.print("Enter your guess: ");
            guess = input.nextInt();

            if (guess < min || guess > max) {
                System.out.println("Your guess is out of range. Please guess again.");
                continue;
            }

            guesses[numGuesses] = guess;
            numGuesses++;

            if (guess == numToGuess) {
                System.out.println("Congratulations! You guessed the number in " + numGuesses + " guesses.");
                break;
            } else if (guess < numToGuess) {
                System.out.println("Your guess is too low.");
            } else {
                System.out.println("Your guess is too high.");
            }
        }

        if (numGuesses == 10) {
            System.out.println("Sorry, you have run out of guesses. The number was " + numToGuess + ".");
        }

        System.out.println("Your guesses were:");
        for (int i = 0; i < numGuesses; i++) {
            System.out.print(guesses[i] + " ");
        }
    }
}

这个游戏会在1到100之间随机选一个数字，然后让玩家猜这个数字。玩家有10次机会猜测，如果在10次之内猜中了，游戏就结束。如果10次之内没有猜中，游戏就失败。在游戏结束之后，程序会打印出玩家的猜测记录。