融合混沌算子和反向学习的差分进化算法matlab
时间: 2023-07-24 08:15:05 浏览: 176
以下是一个简单的 MATLAB 代码示例,演示了如何实现融合混沌算子和反向学习的差分进化算法 RL-CODE:
```matlab
function [best_solution, best_fitness] = RL_CODE(fitness_func, dim, lb, ub, max_iter)
% fitness_func: 适应度函数句柄
% dim: 问题维度
% lb: 下限
% ub: 上限
% max_iter: 最大迭代次数
% 初始化算法参数
CR = 0.5; % 交叉概率
F = 0.5; % 缩放因子
NP = 50; % 种群规模
record = zeros(max_iter, 1); % 记录每一代的最优适应度值
% 初始化种群
pop = lb + (ub - lb) * rand(NP, dim);
fitness = feval(fitness_func, pop);
best_solution = pop(1, :);
best_fitness = fitness(1);
% 初始化混沌序列
x = rand(1);
y = rand(1);
z = rand(1);
for i = 1 : 1000
x_next = y - z;
y_next = x + 0.2 * y;
z_next = 0.2 + z * (x - 10);
x = x_next;
y = y_next;
z = z_next;
end
% 迭代优化
for iter = 1 : max_iter
% 记录每一代的最优适应度值
record(iter) = best_fitness;
% 更新控制参数
if iter > 1
CR = CR + 0.02 * (rand(1) - 0.5);
F = F + 0.02 * (rand(1) - 0.5);
CR = max(0, min(CR, 1));
F = max(0, min(F, 1));
end
% 反向学习机制
if iter > 20 && mod(iter, 10) == 0
[idx, sorted_fitness] = sort(fitness, 'ascend');
pop = pop(sorted_fitness, :);
fitness = fitness(sorted_fitness);
for i = 1 : NP
j = randi([1 NP]);
while j == i
j = randi([1 NP]);
end
if fitness(i) < fitness(j)
pop(i, :) = pop(i, :) + rand(1, dim) .* (pop(j, :) - pop(i, :));
end
end
fitness = feval(fitness_func, pop);
[best_fitness, best_idx] = min(fitness);
best_solution = pop(best_idx, :);
end
% 差分进化算法
for i = 1 : NP
% 选择3个不同的个体
idxs = randperm(NP, 3);
while idxs(1) == i
idxs = randperm(NP, 3);
end
% 生成新个体
v = pop(idxs(1), :) + F * (pop(idxs(2), :) - pop(idxs(3), :));
v = max(v, lb);
v = min(v, ub);
% 混沌序列变换
x = mod(x * 2^32, 1);
y = mod(y * 2^32, 1);
z = mod(z * 2^32, 1);
r = mod(x + y + z, 1);
if rand(1) < r
j = randi([1 dim]);
v(j) = v(j) + randn(1);
end
% 交叉变异
idx = randi([1 dim]);
for j = 1 : dim
if rand(1) < CR || j == idx
pop_new(i, j) = v(j);
else
pop_new(i, j) = pop(i, j);
end
end
end
% 更新种群
fitness_new = feval(fitness_func, pop_new);
for i = 1 : NP
if fitness_new(i) < fitness(i)
pop(i, :) = pop_new(i, :);
fitness(i) = fitness_new(i);
end
if fitness(i) < best_fitness
best_fitness = fitness(i);
best_solution = pop(i, :);
end
end
end
% 返回最优解和最优适应度值
end
```
需要注意的是,上述代码仅为示例,实际应用中可能需要对算法参数进行更细致的调整,以获得更好的优化效果。
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