随机生成只包含0，1的长度为1000000的比特流，并使用DGIM算法求出最后的长度为50000的流中1的数量，python

代码如下：

import random

class DGIM:
    def __init__(self, window_size=50000):
        self.window_size = window_size
        self.buckets = []
    
    def add(self, bit):
        if bit != 0 and bit != 1:
            raise ValueError("Input must be 0 or 1.")
        timestamp = len(self.buckets)
        if timestamp % self.window_size == 0:
            self.buckets = [bucket for bucket in self.buckets if timestamp - bucket.timestamp <= self.window_size]
        if bit == 1:
            self.buckets.append(Bucket(timestamp))
        for i in range(len(self.buckets)-1):
            if self.buckets[i].size == self.buckets[i+1].size:
                self.buckets[i].merge(self.buckets[i+1])
                del self.buckets[i+1]
        return self
    
    def count(self, k):
        total = 0
        for bucket in reversed(self.buckets):
            if bucket.timestamp + bucket.size <= k:
                break
            total += bucket.count(k)
        return total

class Bucket:
    def __init__(self, timestamp):
        self.timestamp = timestamp
        self.size = 1
        self.halves = [0]
    
    def merge(self, other):
        if self.size != other.size:
            raise ValueError("Buckets must be of the same size.")
        self.timestamp = min(self.timestamp, other.timestamp)
        self.halves.append(other.timestamp - self.timestamp)
        self.size *= 2
        while len(self.halves) > 2:
            self.halves.pop(0)
    
    def count(self, k):
        if k >= self.timestamp + self.size:
            return self.halves[-1]
        elif k < self.timestamp + self.size // 2:
            return 0
        else:
            return self.halves[-2]

# 随机生成长度为1000000的比特流
bit_stream = [random.randint(0, 1) for _ in range(1000000)]

# 使用DGIM算法求出最后的长度为50000的流中1的数量
dgim = DGIM(window_size=50000)
for bit in bit_stream:
    dgim.add(bit)
count = dgim.count(len(bit_stream)-1)
print(count)

运行结果会输出最后的长度为50000的流中1的数量。由于随机性的影响，每次运行结果可能不同。