为什么idea提示A "HashMap<Integer, String>" cannot contain a "Byte" in a "Integer" type.
时间: 2023-12-03 08:02:05 浏览: 95
这是因为Java中的HashMap是基于键值对存储数据的,其中键和值都有自己的数据类型。在你的代码中,你定义了一个`HashMap<Integer, String>`,它的键的数据类型是Integer,值的数据类型是String。当你尝试将一个Byte类型的值添加到HashMap中时,由于Byte类型不能转换为Integer类型,所以会出现编译错误。
如果你想要将Byte类型的值添加到HashMap中,你需要将HashMap的键的数据类型改为Byte。例如,你可以这样定义一个HashMap:
```
HashMap<Byte, String> map = new HashMap<>();
```
这样就可以将Byte类型的值添加到HashMap中了。
相关问题
Cannot infer type arguments for HashMap<>
`HashMap<>` is a generic class in Java, which means that it requires type arguments to be specified. You need to specify the type of keys and values. For example, if you want a `HashMap` that maps strings to integers, you would declare it as follows:
```java
HashMap<String, Integer> map = new HashMap<String, Integer>();
```
In this case, `String` is the type of keys, and `Integer` is the type of values. If you want to use type inference, you can omit the type arguments on the right-hand side of the assignment, and Java will infer them from the context:
```java
HashMap<String, Integer> map = new HashMap<>();
```
Here, Java infers the type arguments based on the left-hand side of the assignment.
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