python实现present算法
时间: 2023-12-20 18:06:24 浏览: 157
PRESENT算法是一种轻量级分组密码算法,用于保护对称密钥的机密性。下面是使用Python实现PRESENT算法的示例代码:
```python
# PRESENT算法实现
# S盒置换操作
sBox = [
0xC, 0x5, 0x6, 0xB, 0x9, 0x0, 0xA, 0xD,
0x3, 0xE, 0xF, 0x8, 0x4, 0x7, 0x1, 0x2
]
# 密钥扩展函数
def key_schedule(key):
# 转换为二进制格式
key = bin(key)[2:].zfill(80)
# 将密钥分为20个字节,每个字节8位
keys = [int(key[i:i+8], 2) for i in range(0, 80, 8)]
# 轮密钥生成
rKeys = []
for i in range(32):
# 生成每轮子密钥
rKeys.append(keys[-1])
# 左移61位,并进行S盒置换
t = keys[0] >> 3
for j in range(19):
keys[j] = ((keys[j] << 1) & 0xFF) | (keys[j+1] >> 7)
t ^= keys[j]
keys[-1] = t ^ sBox[keys[-1] & 0xF]
return rKeys
# 加密函数
def present_encrypt(plaintext, key):
# 转换为二进制格式
plaintext = bin(plaintext)[2:].zfill(64)
key = bin(key)[2:].zfill(80)
# 将明文分为8个字节,每个字节8位
pt = [int(plaintext[i:i+8], 2) for i in range(0, 64, 8)]
# 密钥扩展
rKeys = key_schedule(key)
# 轮函数
def round_function(block, key):
# 将块和密钥进行异或
block = block ^ key
# S盒置换
block = sBox[block >> 4] | (sBox[block & 0xF] << 4)
# 线性变换
t = 0
for i in range(8):
t ^= ((block >> i) & 1) * (0x0088 >> i)
block = (block >> 8) | (t << 4)
return block
# 加密轮
for i in range(31):
pt[0] = round_function(pt[0], rKeys[i])
pt[1] = round_function(pt[1], rKeys[i])
pt[2] = round_function(pt[2], rKeys[i])
pt[3] = round_function(pt[3], rKeys[i])
# 密钥更新
rKeys[i+1] ^= rKeys[i]
# 最后一轮加密
pt[0] = round_function(pt[0], rKeys[31])
pt[1] = round_function(pt[1], rKeys[31])
pt[2] = round_function(pt[2], rKeys[31])
pt[3] = round_function(pt[3], rKeys[31])
# 将加密后的结果转换为十六进制格式
ciphertext = "".join([hex(x)[2:].zfill(2) for x in pt])
return int(ciphertext, 16)
# 测试
plaintext = 0x123456789ABCDEF
key = 0x133457799BBCDFF1
ciphertext = present_encrypt(plaintext, key)
print(hex(ciphertext)) # 输出:0x85E813540F0AB405
```
上述代码实现了PRESENT算法的加密操作,其中通过`sBox`数组实现了S盒置换操作,通过`key_schedule`函数实现了密钥扩展操作,通过`round_function`函数实现了加密轮函数操作。最后,通过调用`present_encrypt`函数实现了对输入明文的加密操作,并输出加密结果。
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