TypeError: convolution() missing 1 required positional argument: 'filter'
时间: 2023-10-21 13:05:36 浏览: 125
10种JavaScript最常见的错误(小结)
This error occurs when calling the function `convolution()` without passing in the required argument `filter`.
For example, if the function is defined as:
```python
def convolution(image, filter):
# code to perform convolution
pass
```
And you call the function without passing in the `filter` argument:
```python
image = some_image_array
result = convolution(image)
```
You will get the `TypeError` because the function requires two arguments, but you only passed in one.
To fix this error, make sure to pass in all required arguments when calling the function. For example:
```python
image = some_image_array
filter = some_filter_array
result = convolution(image, filter)
```
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