如何写一个函数实现python中运动的turtle停止
时间: 2023-06-09 07:05:27 浏览: 63
您可以使用turtle库中的turtle.mainloop()方法来使运动的turtle停止运动。该方法将等待用户的交互,并在窗口中单击鼠标或按下键盘时退出程序。您可以在自己的程序中使用此方法,如下所示:
```python
import turtle
# Setup turtle
t = turtle.Turtle()
# Your code for moving the turtle
t.forward(50)
# Stop turtle from moving
turtle.mainloop()
```
在此示例中,运动的turtle将向前移动50个像素。调用turtle.mainloop()将使turtle停止在当前位置运动,等待用户的交互。当使用者按下键盘或单击鼠标时,窗口将关闭并程序结束。
希望对您有所帮助!
相关问题
用python中turtle函数写吴宇哲三个字
以下是用Python中turtle函数写吴宇哲三个字的代码:
```
import turtle
# 设置画笔宽度和颜色
turtle.pensize(10)
turtle.pencolor("blue")
# 写出吴字
turtle.penup()
turtle.goto(-200, 0)
turtle.pendown()
turtle.forward(100)
turtle.right(90)
turtle.forward(150)
turtle.right(90)
turtle.forward(100)
turtle.left(90)
turtle.forward(50)
turtle.left(90)
turtle.forward(100)
turtle.right(90)
turtle.forward(50)
turtle.right(90)
turtle.forward(100)
# 写出宇字
turtle.penup()
turtle.goto(-50, 0)
turtle.pendown()
turtle.right(90)
turtle.forward(150)
turtle.left(90)
turtle.forward(50)
turtle.left(90)
turtle.forward(100)
turtle.right(180)
turtle.forward(100)
# 写出哲字
turtle.penup()
turtle.goto(100, 0)
turtle.pendown()
turtle.right(90)
turtle.forward(150)
turtle.left(90)
turtle.forward(100)
turtle.left(90)
turtle.forward(75)
turtle.right(180)
turtle.forward(150)
turtle.right(180)
turtle.forward(75)
turtle.left(90)
turtle.forward(50)
turtle.left(90)
turtle.forward(75)
# 隐藏画笔
turtle.hideturtle()
# 等待用户关闭窗口
turtle.done()
```
运行代码后,会弹出一个窗口,里面画出了吴宇哲三个字。如果需要保存图片,可以在代码最后加上 `turtle.getcanvas().postscript(file="wuyuzhe.eps")`,然后运行代码保存图片。
使用python中的turtle模块写一个井字游戏
好的,下面是一个使用Python的turtle模块实现的井字游戏的示例代码:
```python
import turtle
# 初始化游戏界面
screen = turtle.Screen()
screen.title("井字游戏")
screen.bgcolor("white")
screen.setup(width=600, height=600)
screen.tracer(0)
# 创建井字棋盘
board = [[" " for _ in range(3)] for _ in range(3)]
# 绘制井字棋盘格子
def draw_board():
turtle.penup()
turtle.goto(-200, 200)
turtle.pendown()
turtle.pensize(3)
for _ in range(2):
turtle.forward(600)
turtle.right(90)
turtle.forward(200)
turtle.right(90)
turtle.penup()
# 绘制棋子
def draw_piece(row, col, piece):
x = -200 + col * 200
y = 200 - row * 200
turtle.goto(x, y)
turtle.pendown()
if piece == "X":
turtle.goto(x + 150, y - 150)
turtle.goto(x, y)
turtle.goto(x + 150, y)
turtle.goto(x, y - 150)
else:
turtle.circle(75)
turtle.penup()
# 处理玩家点击事件
def handle_click(x, y):
col = int((x + 200) // 200)
row = int((200 - y) // 200)
if board[row][col] == " ":
board[row][col] = "X"
draw_piece(row, col, "X")
if check_winner("X"):
turtle.goto(-200, -250)
turtle.write("玩家 X 胜利!", align="center", font=("Arial", 24, "normal"))
turtle.done()
return
if is_board_full():
turtle.goto(-200, -250)
turtle.write("平局!", align="center", font=("Arial", 24, "normal"))
turtle.done()
return
computer_move()
if check_winner("O"):
turtle.goto(-200, -250)
turtle.write("玩家 O 胜利!", align="center", font=("Arial", 24, "normal"))
turtle.done()
return
# 检查是否有玩家获胜
def check_winner(piece):
for i in range(3):
if board[i][0] == board[i][1] == board[i][2] == piece:
return True
if board[0][i] == board[1][i] == board[2][i] == piece:
return True
if board[0][0] == board[1][1] == board[2][2] == piece:
return True
if board[0][2] == board[1][1] == board[2][0] == piece:
return True
return False
# 检查棋盘是否已满
def is_board_full():
for row in board:
if " " in row:
return False
return True
# 计算电脑下棋位置
def computer_move():
for i in range(3):
for j in range(3):
if board[i][j] == " ":
board[i][j] = "O"
draw_piece(i, j, "O")
return
# 注册点击事件处理函数
turtle.onscreenclick(handle_click)
# 绘制井字棋盘
draw_board()
turtle.done()
```
运行以上代码,将会弹出一个窗口,你可以点击窗口中的格子来进行游戏。玩家使用 X 表示,电脑使用 O 表示。当有玩家获胜或者平局时,会在窗口底部显示相应的消息并结束游戏。