帮我完善 def del_tushu_bianhao(head, isBn): while current is not None: if isBn == head.isBn
时间: 2024-05-16 09:14:59 浏览: 14
Sure, here's a possible implementation of the `del_tushu_bianhao` function based on the code you provided:
```python
def del_tushu_bianhao(head, isBn):
# Check if the head node matches the ISBN
if head is not None and head.isBn == isBn:
head = head.next
return head
# Traverse the linked list to find the node before the one to delete
prev = None
current = head
while current is not None and current.isBn != isBn:
prev = current
current = current.next
# If the node is found, remove it by updating the previous node's next pointer
if current is not None:
prev.next = current.next
return head
```
This function takes two arguments: `head`, which is the head node of the linked list, and `isBn`, which is the ISBN of the book to delete. The function first checks if the head node matches the ISBN. If it does, the head is updated to the next node and returned. If not, the function traverses the linked list to find the node before the one to delete. Once the node is found, its `next` pointer is updated to skip over the node to delete. Finally, the function returns the head node, which may have been updated if the head node was deleted.