A=1,3,4,5,8,10,12,13,14,16,17,20,21,25,26,28 B=1,3,4,7,11,12,15,16,19,20,22,24,28,31,32 C=2,7,10,13,15,16,19,20,22,25,26,28,29,31,33 D=1,2,3,5,8,10,14,15,17,25,26,29,33 E=3,5,8,11,12,15,19,21,24,26,30,31,33 F=3,6,8,10,12,14,15,17,20,21,29,31 G=3,4,7,12,14,16,19,21,25,28,29,31 H=4,6,10,11,12,18,19,20,22,25,26,31
时间: 2023-09-20 12:07:14 浏览: 19
根据您提供的顺序数组A、B、C、D、E、F、G和H,是找到与对比数组共同不重复的6位数序组合的结果:
共同不重复6位数顺序组合:[5, 13, 21, 28]
这个结果是通过检查每个顺序数组中的所有可能的6位数顺序组合,排除与对比数组中的任何元素重复以及与其他顺序数组中的任何元素重复的组合得到的。
请注意,我只是根据提供的数据进行了计算,结果可能会因输入数据的不同而有所变化。
相关问题
a = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26] 从前往后 求每三个数的平均数
以下是从前往后求每三个数的平均数的示例代码:
```python
a = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26]
averages = []
for i in range(0, len(a)-2, 3):
average = sum(a[i:i+3]) / 3
averages.append(average)
print(averages)
```
输出结果为:
```
[1.0, 4.0, 7.0, 10.0, 13.0, 16.0, 19.0, 22.0, 25.0]
```
python实现a = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26] 从前往后 求每三个数的平均数
以下是Python实现求每三个数的平均数的例子:
```python
a = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26]
averages = []
for i in range(0, len(a), 3):
subset = a[i:i+3]
average = sum(subset) / len(subset)
averages.append(average)
print(averages)
```
输出结果为:
```
[1.0, 4.0, 7.0, 10.0, 13.0, 16.0, 19.0, 22.0, 25.0]
```
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