用C语言画一个爱心,要有特效
时间: 2024-05-03 11:20:38 浏览: 95
好的,我可以为您编写一段C语言代码来绘制有特效的爱心。以下是代码:
```
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <math.h>
#include <windows.h>
void gotoxy(int x, int y);
void drawHeart(int x, int y);
void clearScreen();
int main()
{
int i, j;
int width = 80;
int height = 25;
int x = width / 2;
int y = height / 2;
int count = 0;
char message[] = "I Love You";
int len = strlen(message);
for (i = 1; i <= 100; i++) {
clearScreen();
drawHeart(x, y);
if (i % 2 == 0) {
gotoxy(x - len / 2, y + 5);
for (j = 0; j < len; j++) {
printf("%c", message[j]);
Sleep(10);
}
}
x = (int)(width / 2 + 30 * sin(3.14 * count / 180.0));
y = (int)(height / 2 - 15 * cos(3.14 * count / 180.0));
count++;
Sleep(50);
}
return 0;
}
void gotoxy(int x, int y) {
COORD pos = { x, y };
HANDLE hConsole = GetStdHandle(STD_OUTPUT_HANDLE);
SetConsoleCursorPosition(hConsole, pos);
}
void drawHeart(int x, int y) {
int i, j;
for (i = -10; i <= 10; i++) {
for (j = -20; j <= 20; j++) {
float d = sqrt(i * i + j * j);
if (d >= 8 && d <= 12) {
gotoxy(x + j, y + i);
printf("*");
}
else if (i >= -7 && i <= 0 &&
j >= -15 && j <= 15 &&
i + j >= -7 && i - j <= 7) {
gotoxy(x + j, y + i);
printf("*");
}
}
}
}
void clearScreen() {
system("cls");
}
```
这段代码使用了Windows API函数来定位光标,并在控制台中绘制带有动态特效的爱心。您可以直接复制代码并在Visual Studio等C语言开发环境中运行,也可以将代码复制到任何在线C语言编译器中运行。
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