在两行中分别输入一个字符串s和整数n,定义一个函数将字符串s循环向右移动n位,n为负数时左移。 若s为空字符串'',则不论n为多少,均输出空字符串''。 如 s='123456' n=3 输出结果:456123 代码框架如下:
时间: 2024-03-21 18:39:46 浏览: 67
好的,这个问题可以用 Python 编写函数解决,代码如下:
```python
def shift_string(s, n):
if s == '':
return ''
else:
n = n % len(s)
return s[-n:] + s[:-n]
s = input() # 获取字符串
n = int(input()) # 获取整数n
result = shift_string(s, n) # 调用函数,得到结果
print(result) # 输出结果
```
您只需要将这段代码复制到 Python 环境中运行,并在两行中分别输入一个字符串和一个整数,程序就会输出将字符串循环向右移动n位后的结果。注意,如果字符串为空字符串'',则不论n为多少,均输出空字符串''。
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