SELECT t1.organization_id, t1.organization_name, t1.road_name, SUM( t2.sj_amount ) xfSjAmount, SUM( t2.jl_amount ) xfJlAmount, SUM( t3.xfGeneralSectionAmount ) xfGeneralSectionAmount, SUM( t3.xfGeneralSectionLength ) xfGeneralSectionLength FROM `main_project` t1 LEFT JOIN mat_approval_project t2 ON t2.main_id = t1.id LEFT JOIN ( SELECT project_id, data_type, SUM( money ) xfGeneralSectionAmount, SUM( mileage ) xfGeneralSectionLength FROM mat_project_pavement_approval GROUP BY project_id ) t3 ON t3.project_id = t2.id WHERE t1.project_general_name = '修复性养护' AND t1.project_category_name = '路面工程' AND t1.process_status = '100' AND t3.data_type = '1' AND t1.road_name = '常祁高速' AND t1.project_year = '2023' 这条sql中t1.road_name多条数据只会展示一个，导致根据t1.road_name查询不到数据

这个问题的原因可能是使用了`LEFT JOIN`，导致t1表中的多个记录与t2和t3表中的记录进行了匹配。如果t1表中有多个记录的`t1.road_name`值相同，那么在`SELECT`语句中使用`SUM`函数对t2和t3表中的记录进行了合并，使得最终查询结果中只有一个记录。这可能导致你根据`t1.road_name`无法查到完整的数据。

为了解决这个问题，你可以考虑在`SELECT`语句中增加`t1.road_name`字段，并在`GROUP BY`子句中包含该字段，以确保t1表中的每个记录都能够被正确匹配和展示。例如：

SELECT
  t1.organization_id,
  t1.organization_name,
  t1.road_name,
  SUM(t2.sj_amount) AS xfSjAmount,
  SUM(t2.jl_amount) AS xfJlAmount,
  SUM(t3.xfGeneralSectionAmount) AS xfGeneralSectionAmount,
  SUM(t3.xfGeneralSectionLength) AS xfGeneralSectionLength
FROM
  main_project t1
  LEFT JOIN mat_approval_project t2 ON t2.main_id = t1.id
  LEFT JOIN (
    SELECT
      project_id,
      data_type,
      SUM(money) AS xfGeneralSectionAmount,
      SUM(mileage) AS xfGeneralSectionLength
    FROM
      mat_project_pavement_approval
    GROUP BY
      project_id
  ) t3 ON t3.project_id = t2.id
WHERE
  t1.project_general_name = '修复性养护'
  AND t1.project_category_name = '路面工程'
  AND t1.process_status = '100'
  AND t3.data_type = '1'
  AND t1.road_name = '常祁高速'
  AND t1.project_year = '2023'
GROUP BY
  t1.organization_id,
  t1.organization_name,
  t1.road_name;

这样，就可以确保每个`t1.road_name`值都能够正确地展示在查询结果中。