A=1,3,4,5,8,10,12,13,14,16,17,20,21,25,26,28 B=1,3,4,7,11,12,15,16,19,20,22,24,28,31,32 C=2,7,10,13,15,16,19,20,22,25,26,28,29,31,33 D=1,2,3,5,8,10,14,15,17,25,26,29,33 E=3,5,8,11,12,15,19,21,24,26,30,31,33 F=3,6,8,10,12,14,15,17,20,21,29,31 G=3,4,7,12,14,16,19,21,25,28,29,31 H=4,6,10,11,12,18,19,20,22,25,26,31
时间: 2023-09-19 22:11:52 浏览: 41
根据提供的数组 A、B、C、D、E、F、G 和 H,以下是所有不重复的六位数顺序组合:
[1, 3, 4, 5, 8, 10]
[1, 3, 4, 5, 8, 12]
[1, 3, 4, 5, 8, 13]
[1, 3, 4, 5, 8, 14]
[1, 3, 4, 5, 8, 16]
[1, 3, 4, 5, 8, 17]
[1, 3, 4, 5, 8, 20]
[1, 3, 4, 5, 8, 21]
[1, 3, 4, 5, 8, 25]
[1, 3, 4, 5, 8, 26]
[1, 3, 4, 5, 8, 28]
[1, 3, 4, 5, 10, 12]
[1, 3, 4, 5, 10, 13]
[1, 3, 4, 5, 10, 14]
[1, 3, 4, 5, 10, 16]
[1, 3, 4, 5, 10, 17]
[1, 3, 4, 5, 10, 20]
[1, 3, 4, 5, 10, 21]
[1, 3, 4, 5, 10, 25]
[1, 3, 4, 5, 10, 26]
[1, 3, 4, 5, 10, 28]
[1, 3, 4, 5, 12, 13]
[1, 3, 4, 5, 12, 14]
[1, 3, 4, 5, 12, 16]
[1, 3, 4, 5, 12, 17]
...(省略部分结果)
这些是所有不重复的六位数顺序组合。请注意,这只是其中的一部分,根据给定的数组,可能会有更多的组合。
相关问题
a = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26] 从前往后 求每三个数的平均数
以下是从前往后求每三个数的平均数的示例代码:
```python
a = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26]
averages = []
for i in range(0, len(a)-2, 3):
average = sum(a[i:i+3]) / 3
averages.append(average)
print(averages)
```
输出结果为:
```
[1.0, 4.0, 7.0, 10.0, 13.0, 16.0, 19.0, 22.0, 25.0]
```
python实现a = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26] 从前往后 求每三个数的平均数
以下是Python实现求每三个数的平均数的例子:
```python
a = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26]
averages = []
for i in range(0, len(a), 3):
subset = a[i:i+3]
average = sum(subset) / len(subset)
averages.append(average)
print(averages)
```
输出结果为:
```
[1.0, 4.0, 7.0, 10.0, 13.0, 16.0, 19.0, 22.0, 25.0]
```
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