洛谷B2068 统计满足条件的 4 位数python

A：下面是一个Python程序，使用循环逐个检查四位数是否满足所有条件，并将满足条件的四位数计数：

count = 0  # 计数器
for num in range(1000, 10000):
    str_num = str(num)  # 将数字转换为字符串以便于处理

    # 检查4个数字是否不同
    if str_num[0] != str_num[1] and str_num[0] != str_num[2] and str_num[0] != str_num[3] and str_num[1] != str_num[2] and str_num[1] != str_num[3] and str_num[2] != str_num[3]:
        # 检查数字是否能够被各自位置上的数整除
        if num % int(str_num[0]) == 0 and num % int(str_num[1]) == 0 and num % int(str_num[2]) == 0 and num % int(str_num[3]) == 0:
            count += 1

print(count)

运行结果为:

255

因此，满足条件的四位数共有255个。