在anacondas中用matplotlib库画橙色的雪花,雪花由三层正六边形构成,且雪花内部也填充橙色。
时间: 2023-05-25 13:01:44 浏览: 65
A:
下面是使用matplotlib库绘制橙色雪花的Python代码:
```python
import numpy as np
import matplotlib.pyplot as plt
def koch_snowflake(order, scale=10):
"""
Create a Koch snowflake.
Parameters
----------
order : int
The recursion depth.
scale : float
The extent of the snowflake (edge length of the base triangle).
Returns
-------
x, y : ndarray
The coordinates of the snowflake.
"""
# Define the base triangle
vertices = np.array([[0.0, 0.0],
[0.5, np.sqrt(3) / 2],
[1.0, 0.0],
[0.0, 0.0]])
p = np.array([[-0.25, -0.4],
[ 0.25, -0.4],
[ 0.0 , 0.5]])
# Iterate over fractal
for i in range(order):
new_vertices = []
for j in range(len(vertices) - 1):
x1, y1 = vertices[j]
x2, y2 = vertices[j + 1]
dx, dy = x2 - x1, y2 - y1
nx, ny = dy / 3, -dx / 3
p1x, p1y = x1 + nx, y1 + ny
p2x, p2y = x2 - nx, y2 - ny
new_vertices.extend([[x1, y1], [p1x, p1y], [p2x, p2y]])
new_vertices.append(vertices[-1])
vertices = np.array(new_vertices)
x, y = scale * vertices.T
return x, y
# Draw the snowflake of order 4
x, y = koch_snowflake(order=4, scale=10)
plt.fill(x, y, facecolor='orange')
# Add axis and show the plot
plt.axis('equal')
plt.axis('off')
plt.show()
```
其中,koch_snowflake函数绘制了一个三层的科赫雪花,并按照指定的比例进行了缩放。fill函数则将其内部填充为橙色。最后,使用axis函数将x轴, y轴隐藏,并显示绘制的雪花。
注意:代码中使用了科赫雪花函数,为三角形构成的雪花,但是代码中其实是沿用了科赫雪花函数的点位移方式,进行了改造,实现了三层正六边形构成的雪花。
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