c++编写一个函数，将一个3乘3的矩阵转置，并显示运行结果

以下是将一个3乘3的矩阵转置的C++代码：

#include <iostream>
using namespace std;

void transpose(int arr[][3]) {
    int temp;
    for (int i = 0; i < 3; i++) {
        for (int j = i + 1; j < 3; j++) {
            temp = arr[i][j];
            arr[i][j] = arr[j][i];
            arr[j][i] = temp;
        }
    }
}

int main() {
    int arr[3][3] = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}};

    cout << "Original matrix:" << endl;
    for (int i = 0; i < 3; i++) {
        for (int j = 0; j < 3; j++) {
            cout << arr[i][j] << " ";
        }
        cout << endl;
    }

    transpose(arr);

    cout << "Transposed matrix:" << endl;
    for (int i = 0; i < 3; i++) {
        for (int j = 0; j < 3; j++) {
            cout << arr[i][j] << " ";
        }
        cout << endl;
    }

    return 0;
}

运行结果为：

Original matrix:
1 2 3
4 5 6
7 8 9
Transposed matrix:
1 4 7
2 5 8
3 6 9