创建函数funx(),保证下面代码能够执行。用两种方法,其中一种方式是函数重载。 int main() { cout<<funx(3, 4, 5)<<endl; //输出3!+4!+5!的值 cout<<funx(3, 4)<<endl; //输出3!+4!的值 cout<<funx(5)<<endl; //输出5!的值 cout<<funx()<<endl; //输出10!的值 return 0; }
时间: 2023-10-30 16:25:42 浏览: 72
好的,下面是两种实现方式:
方法一:函数重载
```python
# 定义函数funx
def factorial(n):
if n == 0:
return 1
else:
return n * factorial(n-1)
def funx(x, y=None, z=None):
if y is None and z is None:
return factorial(10)
elif z is None:
return factorial(x) + factorial(y)
else:
return factorial(x) + factorial(y) + factorial(z)
# 测试代码
print(funx(3, 4, 5)) # 输出3!+4!+5!的值
print(funx(3, 4)) # 输出3!+4!的值
print(funx(5)) # 输出5!的值
print(funx()) # 输出10!的值
```
方法二:默认参数
```python
# 定义函数funx
def factorial(n):
if n == 0:
return 1
else:
return n * factorial(n-1)
def funx(x=0, y=None, z=None):
if x == 0 and y is None and z is None:
return factorial(10)
elif y is None and z is None:
return factorial(x)
elif z is None:
return factorial(x) + factorial(y)
else:
return factorial(x) + factorial(y) + factorial(z)
# 测试代码
print(funx(3, 4, 5)) # 输出3!+4!+5!的值
print(funx(3, 4)) # 输出3!+4!的值
print(funx(5)) # 输出5!的值
print(funx()) # 输出10!的值
```
以上两种方式都可以实现你的需求,具体选择哪种方式取决于你的实际情况。
阅读全文