What is the output of the following code? public class Test { public static void main(String[] args) { java.math.BigInteger x = new java.math.BigInteger("3"); java.math.BigInteger y = new java.math.BigInteger("7"); x.add(y); System.out.println(x); } }
时间: 2024-03-31 08:37:15 浏览: 13
The output of the following code would be "3".
This code creates two BigInteger objects `x` and `y` with values 3 and 7 respectively, and then calls the `add()` method on `x` with `y` as an argument. However, it doesn't store the result of the addition back into `x`. So, `x` remains unchanged and still holds the value 3.
Therefore, when `x` is printed to the console using `System.out.println()`, it will output the value of `x`, which is 3.
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public class Test { public static void main(String[] args) { java.math.BigInteger x = new java.math.BigInteger("3"); java.math.BigInteger y = new java.math.BigInteger("7"); x.add(y); System.out.println(x); } }
这段代码的输出结果是3,因为在这段代码中,虽然我们创建了两个大整数x和y,并使用x.add(y)将它们相加,但是我们没有保存这个结果并将其赋值给x。因此,如果我们想要得到正确的输出结果,应该将x.add(y)的结果赋值给x,如下所示:
```
public class Test {
public static void main(String[] args) {
java.math.BigInteger x = new java.math.BigInteger("3");
java.math.BigInteger y = new java.math.BigInteger("7");
x = x.add(y);
System.out.println(x);
}
}
```
这样,输出结果就会是10。
import java.util.Scanner; package base; public class scaner { public static void main(String[] args) { } } 改错
在代码的开头处移除多余的import语句,将package语句放在import语句后面,同时将类名从"scaner"改为"Scanner",修正后的代码如下:
```java
package base;
import java.util.Scanner;
public class ScannerExample {
public static void main(String[] args) {
// 在这里编写你的代码
}
}
```
请注意,你需要在`main`方法中编写你的代码,这只是一个修正后的代码框架。