ISPA算法求最大流python实现
时间: 2023-07-26 07:07:30 浏览: 49
以下是使用 ISPA 算法求解最大流的 Python 代码实现:
```python
from collections import deque
def bfs(graph, s, t, parent):
visited = [False] * len(graph)
queue = deque()
queue.append(s)
visited[s] = True
while queue:
u = queue.popleft()
for ind, val in enumerate(graph[u]):
if not visited[ind] and val > 0:
queue.append(ind)
visited[ind] = True
parent[ind] = u
return visited[t]
def ispa(graph, source, sink):
n = len(graph)
parent = [-1] * n
max_flow = 0
while bfs(graph, source, sink, parent):
path_flow = float("Inf")
s = sink
while s != source:
path_flow = min(path_flow, graph[parent[s]][s])
s = parent[s]
max_flow += path_flow
v = sink
while v != source:
u = parent[v]
graph[u][v] -= path_flow
graph[v][u] += path_flow
v = parent[v]
return max_flow
```
其中,`graph` 是一个二维列表,表示网络流图。`source` 表示源点,`sink` 表示汇点。函数首先利用 BFS 找到从源点到汇点的一条路径,然后遍历这条路径,找到路径上的最小流量,更新图上的边权值和最大流量。最后返回最大流量即可。
使用示例:
```python
graph = [[0, 16, 13, 0, 0, 0],
[0, 0, 10, 12, 0, 0],
[0, 4, 0, 0, 14, 0],
[0, 0, 9, 0, 0, 20],
[0, 0, 0, 7, 0, 4],
[0, 0, 0, 0, 0, 0]]
source = 0
sink = 5
max_flow = ispa(graph, source, sink)
print("Max Flow:", max_flow)
```
输出结果:
```
Max Flow: 23
```