const tFn: I18nGlobalTranslation = (key: string, ...arg: any[]) => { if (!key) return ''; if (!key.includes('.') && !namespace) return key; return t(getKey(namespace, key), ...(arg as I18nTranslationRestParameters)); }; 代码报错his expression is not callable. Each member of the union type 'ComposerTranslation<Record<string, unknown>, unknown, RemoveIndexSignature<{ [x: string]: LocaleMessageValue<VueMessageType>; }>, never, never, never> | VueI18nTranslation<...>' has signatures, but none of those signatures are compatible with each other.

这个错误通常是由于类型不匹配导致的。可能是因为`t`函数的类型定义不正确，或是在调用`t`函数时传递的参数不符合预期。建议检查以下几点：

1. 确保`t`函数的类型定义正确，应该类似于以下代码：

import { t, Composer } from 'vue-i18n';

type I18nGlobalTranslation = Composer['t'];
const tFn: I18nGlobalTranslation = (key: string, ...args: any[]) => {
  // ...
};

2. 确保在调用`t`函数时传递的参数类型和数量与`t`函数期望的类型和数量相匹配。在这个错误中，可能是`getKey`函数返回了一个错误的键名，导致`t`函数无法找到对应的翻译内容。你可以在调用`t`函数之前，先打印一下`getKey(namespace, key)`的返回值，检查是否符合预期。

如果以上方法都无法解决问题，建议提供更多的代码和错误信息，以便更好地定位问题。

相关问题

import type { createI18n } from 'vue-i18n'; export let i18n: ReturnType<typeof createI18n>; type I18nGlobalTranslation = { (key: string): string; (key: string, locale: string): string; (key: string, locale: string, list: unknown[]): string; (key: string, locale: string, named: Record<string, unknown>): string; (key: string, list: unknown[]): string; (key: string, named: Record<string, unknown>): string; }; type I18nTranslationRestParameters = [string, any]; function getKey(namespace: string | undefined, key: string) { if (!namespace) { return key; } if (key.startsWith(namespace)) { return key; } return `${namespace}.${key}`; } export function useI18n(namespace?: string): { t: I18nGlobalTranslation; } { const normalFn = { t: (key: string) => { return getKey(namespace, key); }, }; if (!i18n) { return normalFn; } const { t, ...methods } = i18n.global; const tFn: I18nGlobalTranslation = (key: string, ...arg: any[]) => { if (!key) return ''; if (!key.includes('.') && !namespace) return key; return t(getKey(namespace, key), ...(arg as I18nTranslationRestParameters)); }; return { ...methods, t: tFn, }; } // Why write this function？ // Mainly to configure the vscode i18nn ally plugin. This function is only used for routing and menus. Please use useI18n for other places // 为什么要编写此函数？ // 主要用于配合vscode i18nn ally插件。此功能仅用于路由和菜单。请在其他地方使用useI18n export const t = (key: string) => key;这段代码报错，帮忙重写

这段代码报错的原因可能是在使用 useI18n 函数时，参数类型不匹配。可以尝试按照下面的方式重写代码：

import { createI18n, LocaleMessages } from 'vue-i18n';

const messages: LocaleMessages = {
  en: {
    // English translations
  },
  zh: {
    // Chinese translations
  },
  // Add more languages and translations as needed
};

const i18n = createI18n({
  locale: 'en',
  messages,
});

export function useI18n(namespace?: string) {
  const normalFn = {
    t: (key: string) => {
      return namespace ? `${namespace}.${key}` : key;
    },
  };

  if (!i18n) {
    return normalFn;
  }

  const { t, ...methods } = i18n.global;

  const tFn: I18nGlobalTranslation = (
    key: string,
    ...arg: I18nTranslationRestParameters
  ) => {
    if (!key) return '';

    if (!key.includes('.') && !namespace) return key;

    return t(namespace ? `${namespace}.${key}` : key, ...arg);
  };

  return {
    ...methods,
    t: tFn,
  };
}

// This function is only used for routing and menus. Please use useI18n for other places
export const t = (key: string) => key;

注意，这里还需要定义 `I18nGlobalTranslation` 和 `I18nTranslationRestParameters` 类型，具体代码如下：

type I18nGlobalTranslation = {
  (key: string): string;
  (key: string, locale: string): string;
  (key: string, locale: string, list: unknown[]): string;
  (key: string, locale: string, named: Record<string, unknown>): string;
  (key: string, list: unknown[]): string;
  (key: string, named: Record<string, unknown>): string;
};

type I18nTranslationRestParameters = [string, ...unknown[]];

优化此代码 const openKeys = ref<string[]>([]) const selectedKeys = ref<string[]>([]) const { currentMenu, currentMenuTree, currentMenuList } = storeToRefs( useLayoutStore(), ) const rootSubmenuKeys = currentMenuList.value.filter((v: any) => { if (v.type === 0) { return v.parentId } }) watch( () => currentMenu, () => { openKeys.value = [currentMenu.value?.parentId] selectedKeys.value = [currentMenu.value?.id] }, { immediate: true }, ) const router = useRouter() /** * 点击事件 * @param e 事件对象 */ const handleClick = (e: any) => { const item = currentMenuList.value.find((_) => _.id === e.key) if (item) { router.push(item.path) } } /** * SubMenu 展开/关闭的回调 * @param e 展开的openKeys */ const onOpenChange = (e: any) => { const latestOpenKey = e.find((key: any) => openKeys.value.indexOf(key) === -1) if (rootSubmenuKeys.indexOf(latestOpenKey) === -1) { openKeys.value = e } else { openKeys.value = latestOpenKey ? [latestOpenKey] : [] } }

There are a few optimizations that could be made to this code:

1. Instead of using `ref` for `openKeys` and `selectedKeys`, you can use `reactive` to make the code more concise:

   const state = reactive({
     openKeys: [],
     selectedKeys: [],
   })

2. Instead of using `storeToRefs` to convert the store state to refs, you can use the `toRefs` function, which is shorter and more concise:

   const { currentMenu, currentMenuTree, currentMenuList } = toRefs(useLayoutStore())

3. Instead of using `watch` to watch the `currentMenu` state changes, you can use a computed property to update the `openKeys` and `selectedKeys` arrays:

   const selectedMenu = computed(() => {
     const item = currentMenuList.value.find((_) => _.id === currentMenu.value?.id)
     return [item?.id] || []
   })

   const parentMenu = computed(() => {
     const item = currentMenuList.value.find((_) => _.id === currentMenu.value?.parentId)
     return [item?.id] || []
   })

   watch([selectedMenu, parentMenu], ([selected, parent]) => {
     state.selectedKeys = selected
     state.openKeys = parent
   })

4. Instead of using `router.push` in the `handleClick` function, you can use the `router.push` method directly in the template:

   <Menu.Item :key="item.id" :to="item.path">{{ item.name }}</Menu.Item>

5. Finally, instead of using `rootSubmenuKeys` to filter the list of menu items, you can use a computed property to filter the list of menu items based on their type:

   const subMenuItems = computed(() => {
     return currentMenuList.value.filter((v: any) => v.type === 0 && v.parentId)
   })

By applying these optimizations, the code can be simplified and made more concise.