用java编写人机交互的井字游戏（从3*3到10*10的棋盘都能实现）

好的，我可以为您提供一个简单的井字游戏的 Java 代码。这个游戏是基于控制台的，可以实现不同大小的棋盘。

import java.util.Scanner;

public class TicTacToe {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int size = 3; // 棋盘大小（默认为3）
        System.out.print("输入棋盘大小（3-10之间的整数）：");
        size = scanner.nextInt();
        char[][] board = new char[size][size]; // 棋盘
        initializeBoard(board); // 初始化棋盘
        char currentPlayer = 'X'; // 当前玩家
        boolean isGameFinished = false; // 游戏是否结束

        while (!isGameFinished) {
            displayBoard(board); // 显示棋盘
            System.out.print("玩家 " + currentPlayer + " 请输入行号和列号（例如：1 2）：");
            int row = scanner.nextInt();
            int col = scanner.nextInt();

            if (isValidMove(board, row, col)) { // 判断是否为有效移动
                board[row][col] = currentPlayer; // 保存玩家的棋子到棋盘中
                if (isGameWon(board, currentPlayer)) { // 判断游戏是否胜利
                    isGameFinished = true;
                    System.out.println("玩家 " + currentPlayer + " 获胜！");
                } else if (isBoardFull(board)) { // 判断棋盘是否已满
                    isGameFinished = true;
                    System.out.println("平局！");
                } else {
                    currentPlayer = (currentPlayer == 'X') ? 'O' : 'X'; // 切换玩家
                }
            } else {
                System.out.println("无效移动，请重新输入！");
            }
        }
        scanner.close();
    }

    // 初始化棋盘
    public static void initializeBoard(char[][] board) {
        for (int i = 0; i < board.length; i++) {
            for (int j = 0; j < board[i].length; j++) {
                board[i][j] = '-';
            }
        }
    }

    // 显示棋盘
    public static void displayBoard(char[][] board) {
        System.out.print(" ");
        for (int i = 0; i < board.length; i++) {
            System.out.print(" " + (i + 1));
        }
        System.out.println();
        for (int i = 0; i < board.length; i++) {
            System.out.print(i + 1);
            for (int j = 0; j < board[i].length; j++) {
                System.out.print(" " + board[i][j]);
            }
            System.out.println();
        }
    }

    // 判断是否为有效移动
    public static boolean isValidMove(char[][] board, int row, int col) {
        if (row < 1 || row > board.length || col < 1 || col > board.length) { // 行号和列号必须在棋盘范围内
            return false;
        }
        if (board[row - 1][col - 1] != '-') { // 该位置已经有棋子
            return false;
        }
        return true;
    }

    // 判断游戏是否胜利
    public static boolean isGameWon(char[][] board, char player) {
        // 判断每一行是否胜利
        for (int i = 0; i < board.length; i++) {
            boolean isWin = true;
            for (int j = 0; j < board[i].length; j++) {
                if (board[i][j] != player) {
                    isWin = false;
                    break;
                }
            }
            if (isWin) {
                return true;
            }
        }

        // 判断每一列是否胜利
        for (int i = 0; i < board.length; i++) {
            boolean isWin = true;
            for (int j = 0; j < board[i].length; j++) {
                if (board[j][i] != player) {
                    isWin = false;
                    break;
                }
            }
            if (isWin) {
                return true;
            }
        }

        // 判断对角线是否胜利
        boolean isWin = true;
        for (int i = 0; i < board.length; i++) {
            if (board[i][i] != player) {
                isWin = false;
                break;
            }
        }
        if (isWin) {
            return true;
        }

        // 判断反对角线是否胜利
        isWin = true;
        for (int i = 0; i < board.length; i++) {
            if (board[i][board.length - i - 1] != player) {
                isWin = false;
                break;
            }
        }
        if (isWin) {
            return true;
        }

        return false;
    }

    // 判断棋盘是否已满
    public static boolean isBoardFull(char[][] board) {
        for (int i = 0; i < board.length; i++) {
            for (int j = 0; j < board[i].length; j++) {
                if (board[i][j] == '-') {
                    return false;
                }
            }
        }
        return true;
    }
}

希望这个代码可以帮助您实现人机交互的井字游戏。