请用C++实现一个链表，把rating.json文件数据读入到链表中,文件里的每条记录包含如下字段信息comment（int）, from,comments,to,score,corp, time，有nlohmann库，样例记录为{ "comment": 0, "from": "北京-北京市-海淀区", "comments": [], "to": "河北省-承德市-隆化县", "score": "0", "corp": "兴铁物流", "time": "1398175318.988036" }

下面是一个简单的链表实现示例：

#include <iostream>
#include <fstream>
#include "nlohmann/json.hpp"

using namespace std;
using json = nlohmann::json;

// 定义链表节点
struct Node {
    int comment;
    string from;
    vector<string> comments;
    string to;
    string score;
    string corp;
    string time;
    Node* next;
};

// 读取json文件并返回json对象
json read_json_file(string filename) {
    ifstream file(filename);
    json j;
    file >> j;
    return j;
}

// 将json对象转换为链表
Node* json_to_list(json j) {
    Node* head = nullptr;
    Node* tail = nullptr;
    for (auto it = j.begin(); it != j.end(); ++it) {
        Node* node = new Node;
        node->comment = it->at("comment");
        node->from = it->at("from");
        node->comments = it->at("comments");
        node->to = it->at("to");
        node->score = it->at("score");
        node->corp = it->at("corp");
        node->time = it->at("time");
        node->next = nullptr;
        if (head == nullptr) {
            head = node;
            tail = node;
        } else {
            tail->next = node;
            tail = node;
        }
    }
    return head;
}

// 输出链表
void print_list(Node* head) {
    while (head != nullptr) {
        cout << head->comment << " " << head->from << " " << head->to << endl;
        head = head->next;
    }
}

int main() {
    string filename = "rating.json";
    json j = read_json_file(filename);
    Node* head = json_to_list(j);
    print_list(head);
    return 0;
}

需要注意的是，这里使用了nlohmann库解析json文件，需要在编译时链接该库。例如，使用g++编译：

g++ -std=c++11 -o main main.cpp -ljsoncpp