0.618方法matlab流程图,0.618法的matlab实现
时间: 2023-10-31 14:56:33 浏览: 92
以下是0.618方法的Matlab实现的流程图:
![0.618方法的Matlab实现的流程图](https://i.imgur.com/3nQUL7H.png)
以下是0.618方法的Matlab代码实现:
```matlab
function [fmin,xmin,iter]=golden_section_search(f,a,b,tol)
% f: the objective function
% a, b: the initial interval
% tol: the tolerance level
% fmin: the minimum value of the function
% xmin: the value of the variable at the minimum point
% iter: the number of iterations
% Define the golden ratio
golden_ratio=(1+sqrt(5))/2;
% Calculate the initial values of x1 and x2
x1=b-(b-a)/golden_ratio;
x2=a+(b-a)/golden_ratio;
% Evaluate the function at the initial values of x1 and x2
f1=f(x1);
f2=f(x2);
% Initialize the iteration counter
iter=0;
% Iterate until the desired tolerance level is reached
while abs(b-a)>tol
iter=iter+1;
% Check which interval is smaller
if f1<f2
b=x2;
x2=x1;
x1=b-(b-a)/golden_ratio;
f2=f1;
f1=f(x1);
else
a=x1;
x1=x2;
x2=a+(b-a)/golden_ratio;
f1=f2;
f2=f(x2);
end
end
% Return the minimum value of the function and the value of the variable at the minimum point
if f1<f2
fmin=f1;
xmin=x1;
else
fmin=f2;
xmin=x2;
end
end
```
该函数的输入参数包括:
- f:目标函数
- a,b:初始区间
- tol:所需的容忍度
该函数的输出参数包括:
- fmin:函数的最小值
- xmin:最小点处的变量值
- iter:迭代次数
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