python分别写出线性插值,多项式插值,样条插值,圆滑插值,三次Hermite插值的代码
时间: 2023-11-19 12:06:30 浏览: 119
好的,下面是关于你提到的插值方法的 Python 代码实现:
线性插值:
```python
def linear_interpolation(x, x_list, y_list):
n = len(x_list)
for i in range(n - 1):
if x_list[i] <= x <= x_list[i + 1]:
slope = (y_list[i + 1] - y_list[i]) / (x_list[i + 1] - x_list[i])
return y_list[i] + slope * (x - x_list[i])
return None
```
多项式插值:
```python
import numpy as np
from numpy.polynomial import Polynomial
def polynomial_interpolation(x, x_list, y_list):
n = len(x_list)
if n < 2 or len(x_list) != len(y_list):
return None
coefficients = np.polyfit(x_list, y_list, n - 1)
polynomial = Polynomial(coefficients)
return polynomial(x)
```
样条插值:
```python
import scipy.interpolate as interp
def spline_interpolation(x, x_list, y_list):
spline = interp.make_interp_spline(x_list, y_list)
return spline(x)
```
圆滑插值:
```python
import scipy.interpolate as interp
def pchip_interpolation(x, x_list, y_list):
interpolation = interp.PchipInterpolator(x_list, y_list)
return interpolation(x)
```
三次 Hermite 插值:
```python
import scipy.interpolate as interp
def hermite_interpolation(x, x_list, y_list, dydx_list):
if len(x_list) != len(y_list) or len(x_list) != len(dydx_list):
return None
interpolation = interp.CubicHermiteSpline(x_list, y_list, dydx_list)
return interpolation(x)
```
以上是根据你提供的插值方法编写的 Python 代码,希望对你有所帮助。
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