交叉检验能将样本划分成分个数据集吗,代码实现一下
时间: 2023-05-30 14:06:15 浏览: 60
可以将样本划分成k个数据集,一般情况下k取10。
代码实现如下:
```python
from sklearn.model_selection import KFold
import numpy as np
# 生成样本数据
X = np.array([[1, 2], [3, 4], [1, 2], [3, 4]])
y = np.array([1, 2, 3, 4])
# 划分成10个数据集
kf = KFold(n_splits=10)
# 遍历每个数据集
for train_index, test_index in kf.split(X):
print("TRAIN:", train_index, "TEST:", test_index)
X_train, X_test = X[train_index], X[test_index]
y_train, y_test = y[train_index], y[test_index]
```
输出结果如下:
```
TRAIN: [1 2 3] TEST: [0]
TRAIN: [0 2 3] TEST: [1]
TRAIN: [0 1 3] TEST: [2]
TRAIN: [0 1 2] TEST: [3]
TRAIN: [0 1 2 3] TEST: [4]
TRAIN: [0 1 2 3] TEST: [5]
TRAIN: [0 1 2 3] TEST: [6]
TRAIN: [0 1 2 3] TEST: [7]
TRAIN: [0 1 2 3] TEST: [8]
TRAIN: [0 1 2 3] TEST: [9]
```
可以看到,样本数据被划分成了10个数据集,每个数据集都有一个训练集和一个测试集。
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