python实验使用turtle库、time库编程实现循环交替绘制当前时间和自己学号的七段数码管,即绘制七段数码管显示当前时间(时分秒),一秒后绘制七段数码管显示自己学号,不断循环。
时间: 2024-03-01 22:53:12 浏览: 31
好的,我来帮你解决这个问题。
首先,我们需要导入turtle库和time库:
```python
import turtle
import time
```
然后,定义一个函数`draw_digit(digit, position)`,用于绘制七段数码管的一个数字。其中,`digit`表示要绘制的数字(0~9),`position`表示数字的位置。
```python
def draw_digit(digit, position):
# 定义七段数码管的线段坐标
segments = [[(0, 50), (0, 60)], [(0, 60), (10, 70)], [(10, 70), (50, 70)],
[(50, 70), (60, 60)], [(60, 60), (60, 50)], [(60, 50), (50, 40)],
[(50, 40), (10, 40)], [(10, 40), (0, 50)], [(0, 50), (10, 60)],
[(10, 60), (50, 60)], [(50, 60), (60, 50)], [(60, 50), (60, 10)],
[(60, 10), (50, 0)], [(50, 0), (10, 0)], [(10, 0), (0, 10)],
[(0, 10), (0, 50)], [(10, 10), (10, 40)], [(50, 10), (50, 40)],
[(10, 10), (20, 20)], [(20, 20), (40, 20)], [(40, 20), (50, 10)],
[(40, 60), (40, 10)]]
# 定义每个数字需要显示的线段
digit_segments = [[0, 1, 2, 4, 5, 6], [2, 5], [0, 2, 3, 4, 6], [0, 2, 3, 5, 6], [1, 2, 3, 5], [0, 1, 3, 5, 6], [0, 1, 3, 4, 5, 6], [0, 2, 5], [0, 1, 2, 3, 4, 5, 6], [0, 1, 2, 3, 5, 6]]
# 获取需要显示的线段
segments_to_draw = [segments[i] for i in digit_segments[digit]]
# 移动到指定位置
turtle.penup()
turtle.goto(position)
turtle.pendown()
# 绘制线段
for segment in segments_to_draw:
turtle.penup()
turtle.goto(segment[0])
turtle.pendown()
turtle.goto(segment[1])
```
接下来,我们定义一个函数`draw_time()`,用于绘制当前时间的七段数码管。
```python
def draw_time():
# 获取当前时间
current_time = time.strftime('%H%M%S')
# 获取每个数字的位置
positions = [(-250, 0), (-150, 0), (-50, 0), (50, 0), (150, 0), (250, 0)]
# 绘制每个数字的七段数码管
for i in range(6):
draw_digit(int(current_time[i]), positions[i])
```
然后,定义一个函数`draw_id()`,用于绘制自己的学号的七段数码管。
```python
def draw_id():
# 获取学号
id = '1234567'
# 获取每个数字的位置
positions = [(-250, 0), (-150, 0), (-50, 0), (50, 0), (150, 0), (250, 0), (350, 0)]
# 绘制每个数字的七段数码管
for i in range(7):
draw_digit(int(id[i]), positions[i])
```
最后,我们可以使用一个无限循环,每隔一秒钟绘制一次当前时间和自己的学号。
```python
while True:
draw_time()
time.sleep(1)
turtle.clear()
draw_id()
time.sleep(1)
turtle.clear()
```
完整代码如下:
```python
import turtle
import time
def draw_digit(digit, position):
# 定义七段数码管的线段坐标
segments = [[(0, 50), (0, 60)], [(0, 60), (10, 70)], [(10, 70), (50, 70)],
[(50, 70), (60, 60)], [(60, 60), (60, 50)], [(60, 50), (50, 40)],
[(50, 40), (10, 40)], [(10, 40), (0, 50)], [(0, 50), (10, 60)],
[(10, 60), (50, 60)], [(50, 60), (60, 50)], [(60, 50), (60, 10)],
[(60, 10), (50, 0)], [(50, 0), (10, 0)], [(10, 0), (0, 10)],
[(0, 10), (0, 50)], [(10, 10), (10, 40)], [(50, 10), (50, 40)],
[(10, 10), (20, 20)], [(20, 20), (40, 20)], [(40, 20), (50, 10)],
[(40, 60), (40, 10)]]
# 定义每个数字需要显示的线段
digit_segments = [[0, 1, 2, 4, 5, 6], [2, 5], [0, 2, 3, 4, 6], [0, 2, 3, 5, 6], [1, 2, 3, 5], [0, 1, 3, 5, 6], [0, 1, 3, 4, 5, 6], [0, 2, 5], [0, 1, 2, 3, 4, 5, 6], [0, 1, 2, 3, 5, 6]]
# 获取需要显示的线段
segments_to_draw = [segments[i] for i in digit_segments[digit]]
# 移动到指定位置
turtle.penup()
turtle.goto(position)
turtle.pendown()
# 绘制线段
for segment in segments_to_draw:
turtle.penup()
turtle.goto(segment[0])
turtle.pendown()
turtle.goto(segment[1])
def draw_time():
# 获取当前时间
current_time = time.strftime('%H%M%S')
# 获取每个数字的位置
positions = [(-250, 0), (-150, 0), (-50, 0), (50, 0), (150, 0), (250, 0)]
# 绘制每个数字的七段数码管
for i in range(6):
draw_digit(int(current_time[i]), positions[i])
def draw_id():
# 获取学号
id = '1234567'
# 获取每个数字的位置
positions = [(-250, 0), (-150, 0), (-50, 0), (50, 0), (150, 0), (250, 0), (350, 0)]
# 绘制每个数字的七段数码管
for i in range(7):
draw_digit(int(id[i]), positions[i])
while True:
draw_time()
time.sleep(1)
turtle.clear()
draw_id()
time.sleep(1)
turtle.clear()
```