编程实现：利用折半查找算法实现在数据序列{2,3,6,33,45,66,88,100}分别查找关键字6和89的结果，找到输出位序，找不到输出相应提示信息。

好的，以下是 Python 代码实现折半查找算法：

def binary_search(array, target):
    left, right = 0, len(array) - 1
    while left <= right:
        mid = (left + right) // 2
        if array[mid] < target:
            left = mid + 1
        elif array[mid] > target:
            right = mid - 1
        else:
            return mid
    return -1

data = [2,3,6,33,45,66,88,100]
target1 = 6
target2 = 89

result1 = binary_search(data, target1)
if result1 == -1:
    print(f"{target1} not found in data.")
else:
    print(f"{target1} found at index {result1} in data.")

result2 = binary_search(data, target2)
if result2 == -1:
    print(f"{target2} not found in data.")
else:
    print(f"{target2} found at index {result2} in data.")

输出结果为：

6 found at index 2 in data.
89 not found in data.

所以，关键字6的位置为2，关键字89在数据中未找到。