c语言输入两个1*n的向量 a和b，并计算a'*b所得的n*n矩阵

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int n;
    printf("Enter the size of vectors: ");
    scanf("%d", &n);

    int *a = (int *)malloc(n * sizeof(int));
    int *b = (int *)malloc(n * sizeof(int));

    printf("Enter the elements of vector a: ");
    for (int i = 0; i < n; i++)
    {
        scanf("%d", &a[i]);
    }

    printf("Enter the elements of vector b: ");
    for (int i = 0; i < n; i++)
    {
        scanf("%d", &b[i]);
    }

    int **matrix = (int **)malloc(n * sizeof(int *));
    for (int i = 0; i < n; i++)
    {
        matrix[i] = (int *)malloc(n * sizeof(int));
    }

    for (int i = 0; i < n; i++)
    {
        for (int j = 0; j < n; j++)
        {
            matrix[i][j] = a[i] * b[j];
        }
    }

    printf("The matrix a'*b is:\n");
    for (int i = 0; i < n; i++)
    {
        for (int j = 0; j < n; j++)
        {
            printf("%d ", matrix[i][j]);
        }
        printf("\n");
    }

    for (int i = 0; i < n; i++)
    {
        free(matrix[i]);
    }
    free(matrix);
    free(a);
    free(b);

    return 0;
}