idea spring security单点登录
时间: 2023-10-09 20:13:32 浏览: 49
Spring Security是一个功能强大的安全框架,可以用于保护和管理应用程序的身份验证和授权。实现单点登录(SSO)的其中一种方法是使用Spring Security与CAS(CentraI Authentication Service)集成。
要在IDEA中实现Spring Security单点登录,你需要按照以下步骤进行操作:
1. 在启动类中添加注解:
```java
@SpringBootApplication
@EnableWebSecurity
public class CasDemoClientApplication {
public static void main(String[] args) {
SpringApplication.run(CasDemoClientApplication.class, args);
}
}
```
2. 在项目工程中添加以下依赖:
```xml
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-security</artifactId>
</dependency>
<dependency>
<groupId>org.springframework.security</groupId>
<artifactId>spring-security-cas</artifactId>
</dependency>
```
3. 添加CAS相关配置项:
```properties
# CAS服务端的地址
cas.server-url-prefix=http://localhost:8080/cas
# CAS服务端的登录地址
cas.server-login-url=http://localhost:8080/cas/login
# 当前服务器的地址(客户端)
cas.client-host-url=http://localhost:8088
```
4. 创建测试Controller类并添加相应的请求映射:
```java
package com.example.casclient.controller;
import org.springframework.security.core.Authentication;
import org.springframework.security.core.context.SecurityContextHolder;
import org.springframework.security.core.userdetails.User;
import org.springframework.stereotype.Controller;
import org.springframework.ui.Model;
import org.springframework.web.bind.annotation.RequestMapping;
import javax.servlet.http.HttpSession;
@Controller
public class IndexController {
@RequestMapping(value = "")
public String index(Model model) {
Authentication auth = SecurityContextHolder.getContext().getAuthentication();
User user = (User) auth.getPrincipal();
System.out.println("当前用户信息:" + user);
model.addAttribute("user", user);
return "index";
}
@RequestMapping(value = "info")
public String info(Model model) {
return "info";
}
}
```
以上是实现IDEA Spring Security单点登录的基本步骤。你可以根据自己的需求进行进一步的配置和扩展。
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