if (!(i + j == n - 1 || j == n - 1 || i == n - 1))
时间: 2023-11-23 15:57:12 浏览: 44
这是一个if语句的条件判断语句,其中i和j是变量,n是一个整数常量。如果i+j等于n-1或者j等于n-1或者i等于n-1,则条件为假,否则条件为真。在Python中,可以将其转换为以下代码:
```python
if not (i + j == n - 1 or j == n - 1 or i == n - 1):
# do something
```
相关问题
Dim n As Integer = CInt(InputBox("请输入一个奇数:"))For i As Integer = 0 To n - 1 Dim line As String = "" For j As Integer = 0 To n - 1 If j = n \ 2 - i Or j = n \ 2 + i Or j = i - n \ 2 Or j = n - 1 - i + n \ 2 Then line &= "*" Else line &= " " End If Next Console.WriteLine(line)Next 改错
在VB中,每个语句必须独立成行,因此你需要在每个语句后面添加换行符。可以改为以下代码:
```vb
Dim n As Integer = CInt(InputBox("请输入一个奇数:"))
For i As Integer = 0 To n - 1
Dim line As String = ""
For j As Integer = 0 To n - 1
If j = n \ 2 - i Or j = n \ 2 + i Or j = i - n \ 2 Or j = n - 1 - i + n \ 2 Then
line &= "*"
Else
line &= " "
End If
Next
Console.WriteLine(line)
Next
```
另外,你需要确保你的代码中没有多余的空格或制表符,这可能导致语法错误。
def roundfun(i0,j0,n,m,num): i=i0 j=j0 if num==num_end: return while j<m: s[i][j]=num j+=1 num+=1 j=m-1 while i<n: s[i][j]=num i+=1 num+=1 i=n-1 while j>=j0: s[i][j]=num j-=1 num+=1 j=j0 while i>i0: s[i][j]=num i-=1 num+=1 roundfun(i0+1,j0+1,n-1,m-1,num)
根据您提供的代码,问题出现在递归函数roundfun` 中。在该函数中,您使用了 `num_end` 变量,但是它没有在函数范围内定义。
请在 `roundfun` 函数内部的开头添加 `num_end = n * m`,以确保变量定义在函数范围内。修改后的代码如下所示:
```python
def roundfun(i0, j0, n, m, num):
num_end = n * m # 添加此行
i = i0
j = j0
if num == num_end:
return
while j < m:
s[i][j] = num
j += 1
num += 1
j = m - 1
while i < n:
s[i][j] = num
i += 1
num += 1
i = n - 1
while j >= j0:
s[i][j] = num
j -= 1
num += 1
j = j0
while i > i0:
s[i][j] = num
i -= 1
num += 1
roundfun(i0 + 1, j0 + 1, n - 1, m - 1, num)
```
请尝试进行这个修改,并重新运行程序。如果还有其他问题,请随时提问。