用A*算法求解八数码问题的源代码
时间: 2024-06-18 18:03:01 浏览: 109
Java-A*算法解决八数码问题算法源码
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A*算法是一种启发式搜索算法,用于解决许多问题,包括八数码问题。下面是使用A*算法求解八数码问题的Python源代码示例:
```
import heapq
def get_manhattan_distance(board):
"""
计算当前棋盘状态和目标状态的曼哈顿距离
"""
distance = 0
for i in range(3):
for j in range(3):
if board[i][j] != 0:
x, y = divmod(board[i][j]-1, 3)
distance += abs(x-i) + abs(y-j)
return distance
def get_successors(board):
"""
获取当前棋盘状态的所有合法后继状态
"""
successors = []
for i in range(3):
for j in range(3):
if board[i][j] == 0:
if i > 0:
new_board = [row[:] for row in board]
new_board[i][j], new_board[i-1][j] = new_board[i-1][j], new_board[i][j]
successors.append(new_board)
if i < 2:
new_board = [row[:] for row in board]
new_board[i][j], new_board[i+1][j] = new_board[i+1][j], new_board[i][j]
successors.append(new_board)
if j > 0:
new_board = [row[:] for row in board]
new_board[i][j], new_board[i][j-1] = new_board[i][j-1], new_board[i][j]
successors.append(new_board)
if j < 2:
new_board = [row[:] for row in board]
new_board[i][j], new_board[i][j+1] = new_board[i][j+1], new_board[i][j]
successors.append(new_board)
return successors
def a_star(start, goal):
"""
A*算法求解八数码问题
"""
heap = [(get_manhattan_distance(start), start)]
visited = set()
while heap:
(distance, current) = heapq.heappop(heap)
if current == goal:
return current
visited.add(str(current))
for successor in get_successors(current):
if str(successor) not in visited:
heapq.heappush(heap, (get_manhattan_distance(successor) + distance + 1, successor))
return None
# 测试代码
start = [[2, 8, 3], [1, 6, 4], [7, 0, 5]]
goal = [[1, 2, 3], [8, 0, 4], [7, 6, 5]]
result = a_star(start, goal)
if result is not None:
print("Found a solution!")
for row in result:
print(row)
else:
print("No solution found.")
```
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