["1","2","3"].map(paseInt)
时间: 2023-09-15 14:23:35 浏览: 53
["1","2","3"].map(parseInt)的结果是[1, NaN, NaN]。这是因为parseInt函数在执行时,会将传入的字符串转换成整数。但是在map函数中,parseInt函数接收三个参数,第一个参数是当前元素的值,第二个参数是当前元素的索引,第三个参数是原始数组。由于parseInt函数只需要一个参数,而map函数会传入三个参数,因此在执行时可能会出现一些意料之外的结果。在这个例子中,parseInt("1", 0, ["1","2","3"])将会返回1,parseInt("2", 1, ["1","2","3"])将会返回NaN,parseInt("3", 2, ["1","2","3"])将会返回NaN。所以最终的结果是[1, NaN, NaN]。<span class="em">1</span><span class="em">2</span><span class="em">3</span>
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