他想学会用数字构建出不同的正方形。 输入格式 输入矩阵的规模，不超过9。 输出格式 输出矩形和正方形 c语言

如果你想在C语言中帮助一个人构建正方形矩阵，你可以编写一个程序来检查给定的矩阵是否是正方形，并且每个元素都是连续的数字。下面是一个简单的示例，该程序接收一个二维数组作为输入，然后检查它能否形成一个正方形：

#include <stdio.h>

// Function to check if a matrix can form a square
int isSquareMatrix(int** arr, int size) {
    if (size == 0 || size > 9) {
        return 0; // Matrix size must be between 1 and 9
    }

    int rowSum[size];
    for (int i = 0; i < size; ++i) {
        rowSum[i] = 0;
        for (int j = 0; j < size; ++j) {
            rowSum[i] += arr[i][j];
        }
    }

    // Check if all row sums are equal and match the total sum
    int totalSum = 0;
    for (int i = 0; i < size; ++i) {
        totalSum += rowSum[i];
        if (!rowSum[i] || totalSum != size * (size * (size + 1) / 2)) {
            return 0;
        }
    }

    // Check if all elements are consecutive
    for (int i = 0; i < size; ++i) {
        for (int j = 0; j < size; ++j) {
            if (arr[i][j] != i * size + j + 1) {
                return 0;
            }
        }
    }

    return 1;
}

int main() {
    int size;
    printf("Enter the size of the matrix (1-9): ");
    scanf("%d", &size);

    int** arr = malloc(size * sizeof(int*));
    for (int i = 0; i < size; ++i) {
        arr[i] = malloc(size * sizeof(int));
    }

    // Assume user input is correct, you may want to validate it
    for (int i = 0; i < size; ++i) {
        for (int j = 0; j < size; ++j) {
            scanf("%d", &arr[i][j]);
        }
    }

    if (isSquareMatrix(arr, size)) {
        printf("The matrix can form a square.\n");
    } else {
        printf("The matrix cannot form a square.\n");
    }

    free(arr);
    return 0;
}