Educational Codeforces Round 146 (Rated for Div. 2)

在Educational Codeforces Round 146 (Rated for Div. 2)比赛中，有关于一个节点数量为n的问题。根据引用的结论，无论节点数量是多少，都可以将其分成若干个大小为2或3的区间使其错排，从而减少花费。根据引用的推导，我们可以通过组合数和差量来表示剩余的花费。而引用进一步推广了这个结论，可以使得任意长度的一段错排花费代价为边权和的两倍，并且通过贪心算法使得更多的边不被使用。以此来解决与节点数量相关的问题。<span class="em">1</span><span class="em">2</span><span class="em">3</span>
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