AttributeError: 'list' object has no attribute 'to

这个错误是因为列表对象没有to_excel或astype属性。在Pandas中，to_excel和astype是DataFrame对象的方法，并不适用于列表对象。要解决这个问题，你需要将列表转换为DataFrame对象，然后再使用to_excel或astype方法。

你可以使用以下代码将列表转换为DataFrame对象并保存为csv文件：

import pandas as pd

my_list = [[1,2,3],[4,5,6],[7,8,9]]
df = pd.DataFrame(my_list)
df.to_csv('example.csv', index=False)

这样就会将列表转换为DataFrame对象，并将其保存为名为example.csv的csv文件。你还可以通过设置index参数来自定义行名。

相关问题

AttributeError: list object has no attribute squeeze

AttributeError: list object has no attribute squeeze是因为在列表对象上调用squeeze方法，而列表对象并没有squeeze方法。squeeze方法是numpy数组对象的方法，用于从数组的形状中删除单维度条目。如果想要使用squeeze方法，需要将列表对象转换为numpy数组对象。

以下是一个例子：

import numpy as np

# 将列表转换为numpy数组
a = np.array([[1, 2, 3], [4, 5, 6], [7, 8, 9]])
print(a)

# 使用squeeze方法删除单维度条目
b = np.squeeze(a)
print(b)

AttributeError: list object has no attribute iloc

`iloc` is a method provided by Pandas DataFrame and Series objects to access data using integer-based indexing. It seems that you are using it with a list object which does not have this attribute.

To resolve this error, you should check if you are working with a Pandas DataFrame or Series object when trying to use `iloc`. If you are working with a list object, you can access its elements using integer-based indexing directly, without using `iloc`.

Here is an example:

my_list = [1, 2, 3, 4, 5]
print(my_list[0])  # Output: 1
print(my_list[1:3])  # Output: [2, 3]

If you are working with a Pandas DataFrame or Series object, make sure to use the correct syntax for `iloc`. Here is an example:

import pandas as pd

df = pd.DataFrame({'a': [1, 2, 3], 'b': [4, 5, 6]})
print(df.iloc[0])  # Output: a    1\nb    4\nName: 0, dtype: int64
print(df.iloc[0, 1])  # Output: 4