(4)编写一个shell脚本,以英文月份名为参数,显示当年该月的日历。
时间: 2024-10-29 17:15:37 浏览: 23
实验三 shell 脚本实验
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Sure, I can help you with that! Here's a simple shell script (bash) that takes an English month name as an argument and displays the calendar for that month:
```bash
#!/bin/bash
# Function to get the number of days in a month based on its name
get_days_in_month() {
case "$1" in
"January"|"March"|"May"|"July"|"August"|"October"|"December")
echo 31
;;
"April"|"June"|"September"|"November")
echo 30
;;
"February")
if [ $(date +%Y) -eq $(date -d "$1 01 +1 year" +%Y) ]; then
echo 29 # Leap year
else
echo 28
fi
;;
*)
echo "Invalid month name"
exit 1
;;
esac
}
# Check if the argument is a valid month name
if [[ ! "$#" -eq 1 || ! "${MONTHS[@]}" =~ ^$1$ ]]; then
echo "Usage: $0 <month_name>"
exit 1
fi
month=$(echo $1 | tr '[:upper:]' '[:lower:]')
days=$(get_days_in_month "$month")
# Display the calendar using cal command (assuming it's installed)
cal -j "$month" "$(expr 1 - $month)"
```
To use this script, save it as a file like `calendar.sh`, give it execute permissions (`chmod +x calendar.sh`), and run it with the desired month name as an argument, e.g., `./calendar.sh february`.
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