Silan SC7A20: 3-Axis Digital Output Accelerometer Sensor Datasheet

datasheet

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INSERT INTO target_table (biz_date, county_name, depart_name, person_uuid, cust_code, cust_name, terminal_level_name, data_gather_type_name, sc_type_name, sc_score, sc_type_name_old, sc_score_old, up) SELECT a.biz_date, a.county_name, a.depart_name, a.person_uuid, a.cust_code, a.cust_name, a.terminal_level_name, a.data_gather_type_name, a.sc_type_name, a.sc_score, b.sc_type_name AS sc_type_name_old, b.sc_score AS sc_score_old, a.sc_score - b.sc_score AS up FROM ads_yh_yx_sctwo a LEFT JOIN ads_yh_yx_sctwo b ON a.cust_code = b.cust_code AND b.biz_date = DATE_FORMAT(DATE_SUB(NOW(), INTERVAL 5 DAY), '%Y%m%d') AND b.person_uuid = '00000000001389361632876_5304_371' WHERE a.biz_date = DATE_FORMAT(DATE_SUB(NOW(), INTERVAL 1 DAY '%Y%m%d') AND a.person_uuid = '00000000001389361632876_5304_371' AND a.sc_type_name != b.sc_type_name AND (a.sc_score - b.sc_score) <> 0 查找此sql的问题

INSERT INTO target_table (biz_date, county_name, depart_name, person_uuid, cust_code, cust_name, terminal_level_name, data_gather_type_name, sc_type_name, sc_score, sc_type_name_old, sc_score_old, up)...

SELECT GDI.P_NO pNo, GDI.P_NAME pName, SO.ORG_NAME pCallDepartment, GTI.P_T_NO ptno, GTI.P_T_NAME ptname, SC.COMPANY_ALL_NAME belongCompany, GTI.FPA_WORK fpahlork, GTI.UPDATE_TIME updateTimeFROM XMUAT.G_TASK_INFO GTILEFT JOIN XMUAT.G_DEMAND_INFO GDI ON GTI.P_NO = GDI.P_NOLEFT JOIN XMUAT.S_COMPANY SC ON SC.COMPANY_NO = GTI.BELONG_COMPANYLEFT JOIN XMUAT.S_ORG SO ON SO.ORG_CODE = GDI.P_CALL_DEPARTMENTWHERE GDI.P_NO IS NOT NULL AND GTI.P_IMPLEMENT_STATUS = '05' AND TO_CHAR(GTI.UPDATE_TIME, 'YYYY-MM-DD HH24:MI:SS') > #{sendTime} AND TO_CHAR(GTI.UPDATE_TIME, 'YYYY-MM-DD HH24:MI:SS') <= TO_CHAR(CURRENT_TIMESTAMP, 'YYYY-MM-DD HH24:MI:SS')这个sql中，我的sendtime 是前端传过来的字符串类型的自定义时间，GTI.update_TIME在数据库中是Timestamp类型，在实体类中是String类型，请问这个在xml中的sql是否有错，要怎么修改

SELECT GDI.P_NO pNo, GDI.P_NAME pName, SO.ORG_NAME pCallDepartment, GTI.P_T_NO ptno, GTI.P_T_NAME ptname, SC.COMPANY_ALL_NAME belongCompany, GTI.FPA_WORK fpahlork, GTI.UPDATE_TIME updateTime ...

sql1 = " SELECT a.biz_date, a.county_name, a.depart_name, a.person_uuid, a.cust_code, a.cust_name, a.terminal_level_name, a.data_gather_type_name, a.sc_type_name, a.sc_score, b.sc_type_name AS sc_type_name_old, b.sc_score AS sc_score_old, a.sc_score-b.sc_score AS up FROM ads_yh_yx_sctwo a LEFT JOIN ads_yh_yx_sctwo b ON a.cust_code = b.cust_code AND b.biz_date = DATE_FORMAT(DATE_SUB(NOW(), INTERVAL 5 DAY), '%Y%m%d') AND b.person_uuid = '00000000001389361632876_5304_371' WHERE a.biz_date = DATE_FORMAT(DATE_SUB(NOW(), INTERVAL 1 DAY), '%Y%m%d') AND a.person_uuid = '00000000001389361632876_5304_371' AND a.sc_type_name != b.sc_type_name AND (a.sc_score - b.sc_score) <> 0; "; $result1 = mysqli_query($conn1, $sql1); 如何把查出来的多条记录再插入对应的表里

SELECT t.*, c.manage_person_mobile as phone FROM ( SELECT a.biz_date, a.county_name, a.depart_name, a.person_uuid, a.cust_code, a.cust_name, a.terminal_level_name, a.data_gather_type_name, a.sc_type_name, a.sc_score, b.sc_type_name AS sc_type_name_old, b.sc_score AS sc_score_old, a.sc_score - b.sc_score AS up FROM ads_yh_yx_sctwo a LEFT JOIN ads_yh_yx_sctwo b ON a.cust_code = b.cust_code AND b.biz_date = DATE_FORMAT(DATE_SUB(NOW(), INTERVAL 2 DAY), '%Y%m%d') AND b.person_uuid = '00000000001389361632876_5304_371' WHERE a.biz_date = DATE_FORMAT(DATE_SUB(NOW(), INTERVAL 1 DAY), '%Y%m%d') AND a.person_uuid = '00000000001389361632876_5304_371' AND a.sc_type_name <> b.sc_type_name AND (a.sc_score - b.sc_score) <> 0 ) t LEFT JOIN ads_yh_yx_customer_login c ON t.cust_code = c.cust_code; 优化以上代码

a.data_gather_type_name, a.sc_type_name, a.sc_score, b.sc_type_name AS sc_type_name_old, b.sc_score AS sc_score_old, a.sc_score - b.sc_score AS up FROM ads_yh_yx_sctwo a LEFT JOIN ads_yh_yx...

SELECT GDI.P_NO pNo, GDI.P _NAME pName, SO.ORG NAME pCallDepartment, GTI.P T NO PTNO, GTI.P_T_NAME PTNAME, SC.COMPANY_ALL_NAME belongCompany, GTI. FPA_WORK fpahlork, GTI.UPDATE_TIME updateTime FROM XMUAT.G TASK INFO GTI LEFT JOIN XMUAT. G _DEMAND_ INFO GDI ON GTI.P_NO = GDI.P_NO LEFT JOIN XMUAT.S_COMPANY SC ON SC. COMPANY_ NO = GTI. BELONG_ COMPANY LEFT JOIN XMUAT.S_ORG SO ON SO. ORG_CODE = GDI.P_CALL_DEPARTMENT WHERE GDI.P_NO IS NOT NULL AND GTI.P_IMPLEMENT_STATUS = '05' AND(GTI.UPDATE_TIME > TO_CHAR(TO_TIMESTAMP( '2023-03-20 16:00:00','YYYY-MM-DD HH24:MI:SS') ,'YYYY-MM-DD HH24:MI:SS') AND GTI.UPDATE TIME <= TO_CHAR(CURRENT_TIMESTAMP) ,'YYYY-MM-DD HH24:MI:SS' )这条是在xml中的sql语句，UPDATE_TIME在返回的实体类是字符串类型，在数据库中保存的是时间戳，那么这个语句有没有错，如果有怎么改

SELECT GDI.P_NO pNo, GDI.P_NAME pName, SO.ORG_NAME pCallDepartment, GTI.P_T_NO ptno, GTI.P_T_NAME ptname, SC.COMPANY_ALL_NAME belongCompany, GTI.FPA_WORK fpahlork, GTI.UPDATE_TIME updateTime ...

WITH a1 as( SELECT c_id, max(score) as score FROM sc GROUP BY c_id ) SELECT sc.s_id,sc.c_id,sc.score from sc INNER JOIN a1 on sc.score = a1.score and a1.c_id = sc.c_id ORDER BY sc.score , sc.c_id GROUP BY sc.c_id,sc.score,sc.s_id HAVING MIN(sc.s_id) = sc.s_id 这个sql有什么语法错误

SELECT sc.s_id, sc.c_id, sc.score FROM sc INNER JOIN a1 ON sc.score = a1.score AND a1.c_id = sc.c_id GROUP BY sc.c_id, sc.score, sc.s_id HAVING MIN(sc.s_id) = sc.s_id ORDER BY sc.score, sc.c_id; ``` ...

这条sql是Oracle 数据库的，请添加分页需求，每次500条SELECT GDI.P_NO AS pNo, GDI.P_NAME AS pName, SO.ORG_NAME AS pCallDepartment, GTI.P_T_NO AS ptno, GTI.P_T_NAME AS ptname, SC.COMPANY_ALL_NAME AS belongCompany, GTI.FPA_WORK AS fpahlork, TO_CHAR(GTI.UPDATE_TIME,'YYYY-MM-DD HH24:MI:SS') AS updateTime FROM XMUAT.G_TASK_INFO GTI LEFT JOIN XMUAT.G_DEMAND_INFO GDI ON GTI.P_NO = GDI.P_NO LEFT JOIN XMUAT.S_COMPANY SC ON SC.COMPANY_NO = GTI.BELONG_COMPANY LEFT JOIN XMUAT.S_ORG SO ON SO.ORG_CODE = GDI.P_CALL_DEPARTMENT WHERE GDI.P_NO IS NOT NULL AND GTI.P_IMPLEMENT_STATUS = '05' AND GTI.UPDATE_TIME > TO_TIMESTAMP(#{sendTime},'YYYY-MM-DD HH24:MI:SS') AND GTI.UPDATE_TIME <= CURRENT_TIMESTAMP

SC.COMPANY_ALL_NAME AS belongCompany, GTI.FPA_WORK AS fpahlork, TO_CHAR(GTI.UPDATE_TIME,'YYYY-MM-DD HH24:MI:SS') AS updateTime, ROW_NUMBER() OVER (ORDER BY GTI.UPDATE_TIME) AS rn FROM XMUAT.G...

insert overwrite table discountdw.dwd_sd_adds_order_bill_inc partition(dt = '2023-06-06') select t1.order_bill_id, t1.counterfoil_no, t1.acceptor, date_format(to_utc_timestamp(cast(t1.expiry_date as bigint) ,'GMT-8'),'YYYY-MM-dd'), t2.company_id, t1.cert_no, t1.company_name, t1.third_order_id, t1.counterfoil_amt/10000, t1.transaction_amt/10000, t1.rate, '3bp' as service_tariffing, ((DATEDIFF(to_utc_timestamp(t1.expiry_date ,'GMT-8'),to_utc_timestamp(t1.transaction_date ,'GMT-8') ) + adjust_days)* 0.0003 (counterfoil_amt))/ 360 as service_fee, 360 as total_days, DATEDIFF(to_utc_timestamp(t1.expiry_date ,'GMT-8'),to_utc_timestamp(t1.transaction_date ,'GMT-8') ) + adjust_days as modulation_date, t3.channel_type, t3.bank_name, date_format(to_utc_timestamp(cast(t1.transaction_date as bigint) ,'GMT-8'),'YYYY-MM-dd'), t1.order_status_code, t1.order_status_msg, t4.fee_amt, t4.status, t1.tenant_id, t5.revenue, to_utc_timestamp(cast(t1.create_date as bigint) ,'GMT-8'), to_utc_timestamp(cast(t1.update_date as bigint) ,'GMT-8') from (select from discountdw.ods_adds_order_bill_inc where dt ='2023-06-06' and channel_id=101110004 )t1 left join (select * from mecdw.ods_company_full where platform_id='sdpjw')t2 on t1.cert_no=t2.cert_no and t1.tenant_id=t2.tenant_id left join discountdw.dim_adds_product_full t3 on t1.partner_id=t3.partner_id and t1.product_id=t3.product_id left join (select * from mecdw.dwd_sc_fee_record_full where dt='2023-06-06' and biz_type=2 ) t4 on t1.order_bill_id=t4.third_id left join (select * from discountdw.ods_sd_order_ext_inc where dt='2023-06-06') t5 on t1.order_bill_id=t5.order_bill_id left join sdpjwdw.dim_holiday_info_full t6 on date_format(to_utc_timestamp(t1.expiry_date ,'GMT-8'),'YYYY-MM-dd') = t6.civic_holiday ;

这是一条 SQL 语句，看起来比较长。以下是一些可以考虑优化的建议： ...LEFT JOIN holiday_data h ON o.expiry_date = DATE_FORMAT(TO_UTC_TIMESTAMP(h.civic_holiday, 'GMT-8'), 'YYYY-MM-dd'); ```

SELECT c.* from ( SELECT a.biz_date,a.cust_code,a.sc_type_name,a.sc_score, b.sc_type_name as sc_type_name_old,b.sc_score as sc_score_old FROM (SELECT * FROM ads_yh_yx_sctwo WHERE biz_date =DATE_FORMAT(DATE_SUB(NOW(), INTERVAL 1 DAY),'%Y%m%d')and person_uuid='00000000001389361632876_5304_371')a LEFT JOIN (SELECT * FROM ads_yh_yx_sctwo WHERE biz_date =DATE_FORMAT(DATE_SUB(NOW(), INTERVAL 3 DAY),'%Y%m%d')and person_uuid='00000000001389361632876_5304_371')b on a.cust_code=b.cust_code )c where sc_type_name != sc_type_name_old and (sc_score-sc_score_old) < 0 请优化以上sql语句

SELECT a.biz_date, a.cust_code, a.sc_type_name, a.sc_score, b.sc_type_name AS sc_type_name_old, b.sc_score AS sc_score_old FROM ads_yh_yx_sctwo a LEFT JOIN ads_yh_yx_sctwo b ON a.cust_code = b.cust_...

SELECT * FROM PMS_SHEET ps, PMS_EQUIPMENT pe WHERE ps.EQUIPMENT_TYPE = pe.EQUIPMENT_TYPE AND ps.IS_ACTIVE = 'Y' AND (ps.ORG_RRN = :orgRrn OR ps.ORG_RRN = 0) AND pe.IS_ACTIVE = 'Y' AND (pe.ORG_RRN = :orgRrn OR pe.ORG_RRN = 0) AND ps.CATEGORY = 'DC' AND (ps."TYPE" <> 'SC' OR (ps."TYPE" ='SC' AND EXISTS ( SELECT 1 FROM PMS_SCHEDULE psd WHERE psd.EQUIPMENT_ID = pe.EQUIPMENT_ID AND psd.SHEET_RRN = ps.OBJECT_RRN AND psd.SCHEDULE_TIME BETWEEN '2023/06/01 00:00:00' AND '2023/06/30 23:59:59' ) ) ) 这个sql执行的结果为什么会报错 ORA-01861: 文字与格式字符串不匹配

SELECT * FROM PMS_SHEET ps, PMS_EQUIPMENT pe WHERE ps.EQUIPMENT_TYPE = pe.EQUIPMENT_TYPE AND ps.IS_ACTIVE = 'Y' AND (ps.ORG_RRN = :orgRrn OR ps.ORG_RRN = 0) AND pe.IS_ACTIVE = 'Y' AND (pe.ORG_RRN = :...

module inner_submod； input logic [9:-1][2:0] sub_input; output logic [9:-1][2:0] sub_output; assign sub_output = sub_input + 1; inner_submod submod1 { .sub_input(st2.st2[0].a), .sub_output(st2.st2[0].a) }; inner_submod submod2 { .sub_input(st2.st2[0].a), .sub_output(st2.st2[0].a) }; inner_submod submod3 { .sub_input(st2.st2[1].a), .sub_output(st2.st2[1].a) }; endmodule module test_top; typedef struct packed { logic [9:-1][2:0] a; } ST1; typedef packed struct { ST1 st1; ST1 st2[2:0]; } ST2; initial begin ST2 st2 = '{ 2'b01, {3'b1, 3'b0, 12'b1} }; $display("st2:%s", st2); end endmodule when compiled by vcs, it reports Error-[UTOPN] Unknown type or port name The type name 'inner_submod' is unknown, or the identifier 'submod1' has not been listed as a port, or the declaration might represent an instance missing parentheses. "sc_assignment_pattern_041.sv',20 Source info: inner_submod submod1{ Error-[SE] Syntax error Following verilog source has syntax error: "sc_assignment_pattern_041.sv", 20 how should I fix these 2 errors? thanks a lot

There are a few issues with the code that need to be fixed. Firstly, in the definition of the `inner_submod` module, the semicolon after the module name should be removed. Secondly, the module ...

Select * From SR_LC_SHIPMENT_RELEASES srf, SR_LC_RELEASE_CONSIGNMENTS cnr, SR_LC_SHPT_RLS_PAYMENTS pay, SR_LC_SHPT_RLS_CHARGES charge Where srf.RELEASE_CONSIGNMENT_UID=cnr.RELEASE_CONSIGNMENT_UID AND srf.SHIPMENT_RELEASE_UID=pay.SHIPMENT_RELEASE_UID(+) AND 'SC'=pay.CHARGE_TYPE(+) AND srf.SHIPMENT_RELEASE_UID=charge.SHIPMENT_RELEASE_UID(+) AND 'SC'=charge.CHARGE_TYPE(+);上面的oracle的写法，请转换为sparksql的写法。

LEFT JOIN SR_LC_SHPT_RLS_PAYMENTS pay ON srf.SHIPMENT_RELEASE_UID = pay.SHIPMENT_RELEASE_UID AND pay.CHARGE_TYPE = 'SC' LEFT JOIN SR_LC_SHPT_RLS_CHARGES charge ON srf.SHIPMENT_RELEASE_UID = charge....

module inner_submod { input logic [9:-1][2:0] sub_input, output logic [9:-1][2:0] sub_output, }; assign sub_output = sub_input +1; endmodule module test_top; typedef struct packed { logic [9:-1][2:0] a; } ST1; typedef struct { ST1 st1; ST1 st2[2:0]; } ST2; inner_submod submod1 { .sub_input(st2.st2[0].a) .sub_output(st2.st2[0].a) }; inner_submod submod2 { .sub_input(st2.st2[0].a) .sub_output(st2.st2[0].a) }; inner_submod submod3 { .sub_input(st2.st2[1].a) .sub_output(st2.st2[1].a) }; initial begin ST2 st2; st2 = '{2'b01, '{3'b1, 3'b0, 12'b1}}; $display("st2:%s",st2); end endmodule this piece of system verilog code, when compiled by vcs, it reports Error-[SE] Syntax error Following verilog source has syntax error : "sc_assignment_pattern_041.sv", 12: token is '{' module inner_submod { how should I modify the code so that it can be compiled successully by vcs? thanks a lot

There are a few syntax errors in the provided code. Here is the corrected code: ``` module inner_submod ( input logic [9:-1][2:0] sub_input, output logic [9:-1][2:0] sub_output ...

inter_n=10 try_n=1 study_data=[] for i in range(try_n): n=neuralNetwork(input_nodes,hidden_nodes,output_nodes,learning_rate) temp=[] for j in range(inter_n): n.train_all() temp.append((n.test(),n.w_in_hid,n.w_hid_out)) temp.sort(key=lambda x:x[0],reverse=True) study_data.append(temp[0]) study_data.sort(key=lambda x:x[0],reverse=True) sc,w_in_hid,w_hid_out=study_data[0] print("max:"+str(sc))

There seems to be a syntax error in the code. The line 'print("max:" str(sc))' should have a comma to separate the two arguments being printed....sc,w_in_hid,w_hid_out=study_data[0] print("max:", sc)

sure. the piece of system verilog code is as below: module inner_submod ( input logic [9:-1][2:0] sub_input, output logic [9:-1][2:0] sub_output ); assign sub_output = sub_input + 1; endmodule module test_top; typedef struct packed { logic [9:-1][2:0] a; } ST1; typedef struct { ST1 st1; ST1 st2[2:0]; } ST2; ST2 st2 = '{st1: {a: '{3'b1, 3'b0, 12'b1}}, st2: '{ '{a: '{3'b1, 3'b0, 12'b1}}, '{a: '{3'b1, 3'b0, 12'b1}}, '{a: '{3'b1, 3'b0, 12'b1}} }}; inner_submod submod1 ( .sub_input(st2.st2[0].a), .sub_output(st2.st2[0].a) ); inner_submod submod2 ( .sub_input(st2.st2[0].a), .sub_output(st2.st2[0].a) ); inner_submod submod3 ( .sub_input(st2.st2[1].a), .sub_output(st2.st2[1].a) ); initial begin $display("st2:%s",st2); end and the error reported by vcs is: Error-[SE] Syntax error Following verilog source has syntax error : "sc_assignment_pattern_041.sv", 12: token is '{' module inner_submod {

The syntax error is caused by the way you are initializing the ST2 struct. Instead of using the '{...}' syntax, you should use the '{...} with {...} with {...}' syntax to initialize nested structs....

SELECT st.s_name, sc.s_score, avg(sc.s_score) from student st left JOIN score sc on st.s_id = sc.s_id GROUP BY sc.s_score HAVING sc.s_score < "60" OR sc.s_score is null要返回两次低于60的用count

SELECT st.s_name, sc.s_score, avg(sc.s_score), COUNT(*) as count FROM student st LEFT JOIN score sc ON st.s_id = sc.s_id WHERE sc.s_score < 60 OR sc.s_score is null GROUP BY st.s_name, sc.s_score ...

下面的这段python代码，哪里有错误，修改一下：import numpy as np import matplotlib.pyplot as plt import pandas as pd import torch import torch.nn as nn from torch.autograd import Variable from sklearn.preprocessing import MinMaxScaler training_set = pd.read_csv('CX2-36_1971.csv') training_set = training_set.iloc[:, 1:2].values def sliding_windows(data, seq_length): x = [] y = [] for i in range(len(data) - seq_length): _x = data[i:(i + seq_length)] _y = data[i + seq_length] x.append(_x) y.append(_y) return np.array(x), np.array(y) sc = MinMaxScaler() training_data = sc.fit_transform(training_set) seq_length = 1 x, y = sliding_windows(training_data, seq_length) train_size = int(len(y) * 0.8) test_size = len(y) - train_size dataX = Variable(torch.Tensor(np.array(x))) dataY = Variable(torch.Tensor(np.array(y))) trainX = Variable(torch.Tensor(np.array(x[1:train_size]))) trainY = Variable(torch.Tensor(np.array(y[1:train_size]))) testX = Variable(torch.Tensor(np.array(x[train_size:len(x)]))) testY = Variable(torch.Tensor(np.array(y[train_size:len(y)]))) class LSTM(nn.Module): def init(self, num_classes, input_size, hidden_size, num_layers): super(LSTM, self).init() self.num_classes = num_classes self.num_layers = num_layers self.input_size = input_size self.hidden_size = hidden_size self.seq_length = seq_length self.lstm = nn.LSTM(input_size=input_size, hidden_size=hidden_size, num_layers=num_layers, batch_first=True) self.fc = nn.Linear(hidden_size, num_classes) def forward(self, x): h_0 = Variable(torch.zeros( self.num_layers, x.size(0), self.hidden_size)) c_0 = Variable(torch.zeros( self.num_layers, x.size(0), self.hidden_size)) # Propagate input through LSTM ula, (h_out, _) = self.lstm(x, (h_0, c_0)) h_out = h_out.view(-1, self.hidden_size) out = self.fc(h_out) return out num_epochs = 2000 learning_rate = 0.001 input_size = 1 hidden_size = 2 num_layers = 1 num_classes = 1 lstm = LSTM(num_classes, input_size, hidden_size, num_layers) criterion = torch.nn.MSELoss() # mean-squared error for regression optimizer = torch.optim.Adam(lstm.parameters(), lr=learning_rate) # optimizer = torch.optim.SGD(lstm.parameters(), lr=learning_rate) runn = 10 Y_predict = np.zeros((runn, len(dataY))) # Train the model for i in range(runn): print('Run: ' + str(i + 1)) for epoch in range(num_epochs): outputs = lstm(trainX) optimizer.zero_grad() # obtain the loss function loss = criterion(outputs, trainY) loss.backward() optimizer.step() if epoch % 100 == 0: print("Epoch: %d, loss: %1.5f" % (epoch, loss.item())) lstm.eval() train_predict = lstm(dataX) data_predict = train_predict.data.numpy() dataY_plot = dataY.data.numpy() data_predict = sc.inverse_transform(data_predict) dataY_plot = sc.inverse_transform(dataY_plot) Y_predict[i,:] = np.transpose(np.array(data_predict)) Y_Predict = np.mean(np.array(Y_predict)) Y_Predict_T = np.transpose(np.array(Y_Predict))

training_data = sc.fit_transform(training_set) # 定义窗口长度 seq_length = 1 # 对数据进行窗口划分 x, y = sliding_windows(training_data, seq_length) # 划分训练集和测试集 train_size = int(len(y) * ...

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SC7A20规格书(带寄存器描述).pdf

SC7A20说明书，GSENSOR

SC7A20说明书_0.8(带寄存器描述)1

WITH a1 as( SELECT c_id, max(score) as score FROM sc GROUP BY c_id ) SELECT sc.s_id,sc.c_id,sc.score from sc INNER JOIN a1 on sc.score = a1.score and a1.c_id = sc.c_id ORDER BY sc.score , sc.c_id GROUP BY sc.c_id,sc.score,sc.s_id HAVING MIN(sc.s_id) = sc.s_id 这个sql有什么语法错误

SELECT st.s_name, sc.s_score, avg(sc.s_score) from student st left JOIN score sc on st.s_id = sc.s_id GROUP BY sc.s_score HAVING sc.s_score < "60" OR sc.s_score is null要返回两次低于60的用count

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