C语言实现的俄罗斯方块代码

#include<stdio.h>
 #include<stdlib.h>
 #include<windows.h>
 #include<time.h>
 #include<conio.h>

 #define MOD 28
 #define SIZE_N 19
 #define SIZE_M 12

 int cur_x,cur_y;
 int score,mark,next,map[SIZE_N][SIZE_M],Gamespeed=300;

 int shape[28][6]={
         {0,-1,0,-2,1,0}, {0,1,1,0,2,0}, {-1,0,0,1,0,2}, {0,-1,-1,0,-2,0},
         {0,-1,0,1,-1,0}, {0,1,1,0,-1,0}, {1,0,0,-1,0,1}, {1,0,-1,0,0,-1},
         {-1,1,0,1,1,0}, {0,-1,1,0,1,1}, {-1,0,0,-1,1,-1}, {-1,-1,-1,0,0,1},
         {-1,0,0,1,1,1}, {0,1,1,-1,1,0}, {-1,0,0,1,1,1}, {0,1,1,-1,1,0},
         {-1,0,0,-1,0,-2}, {-1,0,-2,0,0,1}, {0,1,0,2,1,0}, {0,-1,1,0,2,0},
         {0,1,1,0,1,1}, {0,-1,1,0,1,-1}, {-1,0,0,-1,-1,-1}, {-1,0,-1,1,0,1},
         {0,1,0,2,0,3}, {1,0,2,0,3,0}, {0,-1,0,-2,0,-3}, {-1,0,-2,0,-3,0}
 };

 void gotoxy(int x,int y){
         COORD c;
         c.X=x-1; c.Y=y-1;
         SetConsoleCursorPosition (GetStdHandle(STD_OUTPUT_HANDLE), c);
 }
 void Gameover(){

         int i,j,flag=0;
         for(j=1;j<SIZE_M-1;j++){
                 if(map[1][j]!=0){
                         flag=1;break;
                 }
         }
         if(flag==1){
                 for(i=1;i<SIZE_N-1;i++){
                         gotoxy(2,i+1);
                         for(j=1;j<SIZE_M-1;j++){
                                 printf("□");
                         }puts("");
                 }
                 gotoxy(7,9);
                 printf("GAME OVER!");
                 gotoxy(1,SIZE_N+1);
                 exit(0);
         }
 }
 void ShowMap(int id){
         int i,j;
         gotoxy(1,1);
         if(id!=-1){
                 for(i=0;i<SIZE_N;i++){
                         for(j=0;j<SIZE_M;j++){
                                 if(i==0&&j==0 || i==0&&j==SIZE_M-1 || j==0&&i==SIZE_N-1 || j==SIZE_M-1&&i==SIZE_N-1)printf(" ");
                                 else if(i==0 || i==SIZE_N-1)printf("--");
                                 else if(j==0 || j==SIZE_M-1)printf("|");
                                 else if(map[i][j]==2) printf("■");
                                 else if(i==cur_x+shape[id][0] && j==cur_y+shape[id][1] ||